Log(2x*12)=3
10^3=2x*12
1000=24x
1000/24=x
x=41.667
Answer: $30.60
Step-by-step explanation:
multiply 3.4% or 0.034 in decimal form, by 900, and that’s your interest
Answer:

Step-by-step explanation:
It's easy you are
kid♂️♂️♂️
Answer:
$42,890
Step-by-step explanation:
The standard form for an exponential equation is

where a is the initial amount value and b is the growth rate or decay rate and t is the time in years. Since we are dealing with money amounts AND this is a decay problem, we can rewrite accordingly:

where A(t) is the amount after the depreciation occurs, r is the interest rate in decimal form, and t is the time in years. We know the initial amount (70,000) and the interest rate (.04), but we need to figure out what t is. If the car was bought in 2006 and we want its value in 2018, a total o 12 years has gone by. Therefore, our equation becomes:
or, after some simplification:

First rais .96 to the 12th power to get
A(t) = 70,000(.6127097573)
and then multiply.
A(t) = $42,890
Answer:
9. <em><u>1</u></em><em><u>0</u></em>
10. <em><u>1</u></em><em><u>0</u></em><em><u>/</u></em><em><u>2</u></em><em><u>6</u></em>
11.<em><u>2</u></em><em><u>4</u></em><em><u>/</u></em><em><u>2</u></em><em><u>6</u></em>
12.<em><u>2</u></em><em><u>4</u></em><em><u>/</u></em><em><u>1</u></em><em><u>0</u></em>
Step-by-step explanation:
9.<em><u>U</u></em><em><u>sing </u></em><em><u>Pythagoras</u></em><em><u> Theorem</u></em>
<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>P </u></em><em><u>=</u></em><em><u> </u></em><em><u>√</u></em><em><u>(</u></em><em><u>H</u></em><em><u>²</u></em><em><u>-</u></em><em><u>B</u></em><em><u>²</u></em><em><u>)</u></em>
<em><u>Where</u></em><em><u>,</u></em>
<em><u>P </u></em><em><u>=</u></em><em><u> </u></em><em><u>perpendicular</u></em><em><u> </u></em>
<em><u>B </u></em><em><u>=</u></em><em><u> </u></em><em><u>Base</u></em>
<em><u>H </u></em><em><u>=</u></em><em><u> </u></em><em><u>Hypotenuse</u></em>
<em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u> </u></em><em><u>P/</u></em><em><u>H</u></em>
<em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u> </u></em><em><u>B/</u></em><em><u>H</u></em>
<em><u>1</u></em><em><u>2</u></em><em><u>.</u></em><em><u> </u></em><em><u>P/</u></em><em><u>B</u></em>