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artcher [175]
3 years ago
8

Apply the Pythagorean Theorem to find the distance between points A and C.

Mathematics
1 answer:
-Dominant- [34]3 years ago
6 0
When using Pythagorean Theorem you get C !!!
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Solve log 2x + log 12 =3 can
stepan [7]
Log(2x*12)=3
10^3=2x*12
1000=24x
1000/24=x
x=41.667
3 0
3 years ago
Please Help! April took out a $900 loan from the bank. At the end of the 5 years, a 3.4%interest rate. How much interest does sh
OleMash [197]

Answer: $30.60

Step-by-step explanation:

multiply 3.4% or 0.034 in decimal form, by 900, and that’s your interest

5 0
3 years ago
Please help me with this question! thank you :)
nikdorinn [45]

Answer:

2 + 2 = 0

Step-by-step explanation:

It's easy you are

kid‍♂️‍♂️‍♂️

3 0
2 years ago
A car, originally valued at 70,000 in 2006 depreciates exponentially at a rate of 4% each year. Round the expected value of the
lora16 [44]

Answer:

$42,890

Step-by-step explanation:

The standard form for an exponential equation is

y=a(b)^x

where a is the initial amount value and b is the growth rate or decay rate and t is the time in years.  Since we are dealing with money amounts AND this is a decay problem, we can rewrite accordingly:

A(t)=a(1-r)^t

where A(t) is the amount after the depreciation occurs, r is the interest rate in decimal form, and t is the time in years.  We know the initial amount (70,000) and the interest rate (.04), but we need to figure out what t is.  If the car was bought in 2006 and we want its value in 2018, a total o 12 years has gone by.  Therefore, our equation becomes:

A(t)=70,000(1-.04)^{12} or, after some simplification:

A(t)=70,000(.96)^{12}

First rais .96 to the 12th power to get

A(t) = 70,000(.6127097573)

and then multiply.

A(t) = $42,890

8 0
3 years ago
Please help. Will give Brainliest!!
Natalija [7]

Answer:

9. <em><u>1</u></em><em><u>0</u></em>

10. <em><u>1</u></em><em><u>0</u></em><em><u>/</u></em><em><u>2</u></em><em><u>6</u></em>

11.<em><u>2</u></em><em><u>4</u></em><em><u>/</u></em><em><u>2</u></em><em><u>6</u></em>

12.<em><u>2</u></em><em><u>4</u></em><em><u>/</u></em><em><u>1</u></em><em><u>0</u></em>

Step-by-step explanation:

9.<em><u>U</u></em><em><u>sing </u></em><em><u>Pythagoras</u></em><em><u> Theorem</u></em>

<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>P </u></em><em><u>=</u></em><em><u> </u></em><em><u>√</u></em><em><u>(</u></em><em><u>H</u></em><em><u>²</u></em><em><u>-</u></em><em><u>B</u></em><em><u>²</u></em><em><u>)</u></em>

<em><u>Where</u></em><em><u>,</u></em>

<em><u>P </u></em><em><u>=</u></em><em><u> </u></em><em><u>perpendicular</u></em><em><u> </u></em>

<em><u>B </u></em><em><u>=</u></em><em><u> </u></em><em><u>Base</u></em>

<em><u>H </u></em><em><u>=</u></em><em><u> </u></em><em><u>Hypotenuse</u></em>

<em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u> </u></em><em><u>P/</u></em><em><u>H</u></em>

<em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u> </u></em><em><u>B/</u></em><em><u>H</u></em>

<em><u>1</u></em><em><u>2</u></em><em><u>.</u></em><em><u> </u></em><em><u>P/</u></em><em><u>B</u></em>

3 0
3 years ago
Read 2 more answers
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