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Ilya [14]
3 years ago
15

Mr. Sims wants to buy a new truck. He sold his old truck for $3,582, and he has $4,979 in the bank. If a new truck costs $9,005,

how much more money does he need in order buy the new truck?
Mathematics
1 answer:
Colt1911 [192]3 years ago
7 0

Answer:

$444

Step-by-step explanation:

3,582 + 4,979 = 8,561

9,005 - 8,561 = 444

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Solve for AB. Round your answer to the nearest tenth if necessary.
NeTakaya

Answer:

See Below

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You want to find AB.

They give the equation for AB, BC, and AC

AC - BC = AB

substitute the equations

(30) - (8x + 3) = 6x + 8

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3 years ago
Read 2 more answers
Ex 4.8<br> 14) integrate 3^(2x-1)
sesenic [268]
Take the integral:

\large\begin{array}{l} \mathsf{\displaystyle\int\!3^{2x-1}\,dx}\\\\ =\mathsf{\displaystyle\int\!\frac{1}{2}\cdot 2\cdot 3^{2x-1}\,dx}\\\\ =\mathsf{\displaystyle\frac{1}{2}\int\!3^{2x-1}\cdot 2\,dx\qquad(i)} \end{array}


\large\begin{array}{l} \textsf{Substitute}\\\\ \mathsf{2x-1=u\quad\Rightarrow\quad 2\,dx=du}\\\\\\ \textsf{so (i) becomes}\\\\ =\mathsf{\displaystyle\frac{1}{2}\int\!3^u\,du}\\\\ =\mathsf{\dfrac{1}{2}\cdot \dfrac{1}{\ell n\,3}\,3^u+C}\\\\ =\mathsf{\dfrac{1}{2\,\ell n\,3}\,3^{2x-1}+C} \end{array}


\large\begin{array}{l} \boxed{\begin{array}{c}\mathsf{\displaystyle\int\!3^{2x-1}\,dx=\frac{1}{2\,\ell n\,3}\,3^{2x-1}+C} \end{array}}\qquad\checkmark \end{array}


<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2154165


\large\textsf{I hope it helps. :-)}
</span>

Tags: <em>integrate indefinite integral substitution exponential base logarithm log ln composite integral calculus

</em>
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3 years ago
Can someone please help me
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