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tester [92]
3 years ago
7

What is the absolute value of -36

Mathematics
1 answer:
goblinko [34]3 years ago
3 0

Answer:

36

Step-by-step explanation:

absolute value of -36 is 36

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Since it is given that AB ≅ AC, it must also be true that AB = AC. Assume ∠B and ∠C are not congruent. Then the measure of one a
BartSMP [9]

Answer: The required conclusion is

"if in triangle ABC, AB ≅ AC, then ∠B and ∠C must be congruent".

Step-by-step explanation:  Given that in triangle ABC,  AB ≅ AC, implies that AB = AC must be true. We are given to assume ∠B and ∠C are not congruent. Then the measure of one angle is greater than the other.

If m∠B > m∠C, then AC > AB because of the triangle parts relationship theorem.

For the same reason, if m∠B < m∠C, then AC < AB.

This is a contradiction to the given information.

We are to state the conclusion.

Since in the beginning, it is given that AB ≅ AC and we have assumed that ∠B and ∠C are not congruent, so

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That is, ∠B and ∠C must be congruent.

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if in triangle ABC, AB ≅ AC, then ∠B and ∠C must be congruent.

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What is the least common multiple of 3 and 9
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Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma
Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with \mu = 112 inches and \sigma = 14 inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - \mu = 112 inches

Standard deviation - \sigma = 14 inches

The z-score formula is given by, Z=\frac{x-\mu}{\sigma}

Now,

P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})

P(X>140)=P(Z>\frac{140-112}{14})

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P(X>140)=P(Z>2)

P(X>140)=1-P(Z

The Z-score value we get is from the Z-table,

P(X>140)=1-0.9772

P(X>140)=0.0228

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

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