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GarryVolchara [31]
2 years ago
10

How dose the graph of g(x)=x+5 compares with the graph of the parent function, f(x)=x?

Mathematics
2 answers:
mamaluj [8]2 years ago
8 0

Answer:

really hard

Step-by-step explanation:

i can even solve it

PolarNik [594]2 years ago
4 0
It's A it's shifted by 5 units up and u can see that when you visualise the two graphs
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Can someone help answer at least one? :) ty
Vika [28.1K]

Answer:

Step-by-step explanation:

a). Ratio of OP and RT = \frac{OP}{RT}

                                     = \frac{12}{3.6}

                                     = \frac{10}{3}

b). Since ΔOPQ ~ ΔRTS, their corresponding sides will be proportional.

    \frac{OQ}{RS}=\frac{OP}{RT}

    \frac{OQ}{4.5}=\frac{10}{3}

    OQ = \frac{10\times 4.5}{3}

    OQ = 15 cm

c). m∠P = m∠T = 60°

d). m∠Q = m∠S

    By applying angle sum theorem in ΔRST,

    m∠R + m∠S + m∠T = 180°

    26° + m∠S + 60° = 180°

    m∠S = 180° - 86°

             = 94°

    Therefore, m∠Q = m∠S = 94°

3 0
3 years ago
What's the distance between (-5,-6) and (4,2)
Andreyy89
The negitives are far from the 0 so its less than the non negitives

5 0
3 years ago
What is 100 * 100 the anser is 1000
Volgvan

Answer:

yes

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Factor this expression completely and then place the factors in the proper location on the grid.
Sindrei [870]
X^2 - 9 =
(x + 3)(x - 3)
4 0
2 years ago
Read 2 more answers
What is the distance between coordinates (-6.25,5) and (-3.75,2)
Oksi-84 [34.3K]

Answer:

\sqrt{15.25}

Step-by-step explanation:

To find the distance, we can use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} when the given points are (x_1,y_1) and (x_2,y_2)

Plug in the points (-6.25,5) and (-3.75,2)

d=\sqrt{(-6.25-x_1)^2+(5-y_1)^2}\\d=\sqrt{(-6.25-(-3.75))^2+(5-2)^2}\\d=\sqrt{(-6.25+3.75)^2+(5-2)^2}\\d=\sqrt{(-2.5)^2+(3)^2}\\d=\sqrt{6.25+9}\\d=\sqrt{15.25}

Therefore, the distance between the two coordinates is \sqrt{15.25}, or approximately 3.91.

I hope this helps!

6 0
2 years ago
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