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kozerog [31]
2 years ago
15

Math help mee plzzzzzz THERE IS A ATTACHMENT SO WAIT AT LEAST 30 SECONDS PLZZZZ

Mathematics
2 answers:
seraphim [82]2 years ago
7 0
75 mph because you divide 337.5 by 4.5
eduard2 years ago
5 0
Since he did #1

i'll do number 21 which is C 
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Which function represents the graph of h(x)=2|x+3|−1 after it is translated 2 units right?
harina [27]

\bf ~\hspace{10em}\textit{function transformations} \\\\\\ \begin{array}{llll} f(x)= A( Bx+ C)^2+ D \\\\ f(x)= A\sqrt{ Bx+ C}+ D \\\\ f(x)= A(\mathbb{R})^{ Bx+ C}+ D \end{array}\qquad \qquad \begin{array}{llll} f(x)=\cfrac{1}{A(Bx+C)}+D \\\\\\ f(x)= A sin\left( B x+ C \right)+ D \end{array} \\\\[-0.35em] ~\dotfill\\\\ \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\ \bullet \textit{ flips it upside-down if } A\textit{ is negative}

\bf ~~~~~~\textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if } B\textit{ is negative}\\ ~~~~~~\textit{reflection over the y-axis} \\\\ \bullet \textit{ horizontal shift by }\frac{ C}{ B}\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}

\bf ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by } D\\ ~~~~~~if\ D\textit{ is negative, downwards}\\\\ ~~~~~~if\ D\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{ B}

now with that template in mind

\bf h(x)=\stackrel{A}{2}|\stackrel{B}{1}x+\stackrel{C}{3}|\stackrel{D}{-1}\qquad \qquad \stackrel{\textit{C=C-2 a translation to the right}}{h(x)=2|x\boxed{+3-2}|-1} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill h(x)=2|x+1|-1~\hfill

8 0
3 years ago
Read 2 more answers
Nancy is running on a trail that's 5.3 miles long. After 20 minutes, she has run 1.45 miles. Write an addition to fine how much
mars1129 [50]

Answer:

5.3-1.45=3.85

Step-by-step explanation:

she has 3.85 miles left to go because she already ran 1.45 and if you subtract that from the 5.3 you get 3.85 left to run.

5 0
3 years ago
Complete the steps, which describe how to find the area of the shaded portion of the circle. 1. Find the area of the sector by m
Serggg [28]

The area of the sector is found by multiplying the area of the circle and the ratio of the angle subtended (measure of the central angle) by the sector to 360.

<h3>How to find the area of a sector?</h3>

1) The formula for area of a sector of a circle is;

A = (θ/360) * πr²

where πr² is area of circle

θ is the angle subtended by the sector

Thus, we conclude that the area of the sector is found by multiplying the area of the circle and the ratio of the angle subtended (measure of the central angle) by the sector to 360.

2) The area of the triangle formed as part of the segment is subtracted from from the area of the sector.

Read more about Area of Sector at; brainly.com/question/22972014

#SPJ1

4 0
1 year ago
Read 2 more answers
Use the given information to determine which of the following relationships
Anon25 [30]

Answer:

B. ∆LMN ≅ ∆OPQ because of ASA

Step-by-step explanation:

Two triangles are congruent if two angles and an included side of one triangle are congruent to two corresponding angles and a corresponding included side of the other.

From the information given, we have:

Two angles (<L and <M) in ∆LMN that are congruent to two corresponding angles (<O and <P) in ∆OPQ.

Also, included side in both triangles are congruent (ML ≅ PO).

Therefore, ∆LMN ≅ ∆OPQ by the ASA Theorem.

6 0
3 years ago
PLS HELP IF YOU CAN!THIS IS DUE IN 30 MINUTES :(
ExtremeBDS [4]

Answer:

Length: 20 or 40 feet

Width: 40 or 20 feet

Step-by-step explanation:

Area = 800 = length*width = x*(60-x)= 60x - x^2

- x^2 + 60x - 800 = 0

x = 20

Or x = 40

So length can be either 20 feet or 40 feet and width can be 40 (60-20) or 20 (60-40)

6 0
2 years ago
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