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Hunter-Best [27]
3 years ago
14

In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 9 boys and

6 girls are competing, how many different ways could the six medals possibly be given out?
Mathematics
1 answer:
Lady_Fox [76]3 years ago
4 0

Answer:

d

Step-by-step explanation:

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How’s do I simplify this
Sati [7]
1/8x(16m-8)-17


Factor out 8 from the expression

1/8x8(2m-1)-17


Reduce the numbers with greatest common divisor 8

(2m-1)-17


Remove unnecessary parenthesis


2m-1-17


Calculate the difference


2m-18
3 0
3 years ago
Read 2 more answers
Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
3 years ago
What number is 80% of 90?
Lerok [7]
The answer is 72

b/c 80% is equal to .80 

so you do 90x.80
4 0
3 years ago
The equation through the point (5,3) and is parallel the equation y=2/5x+7​
nignag [31]

Answer:

Point - Slope Form: (y - 3) = 0.4(x - 5)

Slope - Intercept Form: y = 0.4x + 1

Step-by-step explanation:

Well if it's parallel, they have the same slope

Slope = 0.4

I'll do it in two forms:

Point - Slope Form: (y - 3) = 0.4(x - 5)

Slope - Intercept Form: y = 0.4x + b

3 = 2 + b

b = 1

y = 0.4x + 1

I might be wrong

3 0
3 years ago
Can anyone help me with this?
Neko [114]

Answer:

the answer would be 5

Step-by-step explanation:

because if there was 15 truth or false questions that would be 45 points and if there where 5 essay questions that would be 55 questions 45+55=100 points and 15+5 questions is 20 questions so there would be 5 essay questions.

3 0
2 years ago
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