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Assoli18 [71]
3 years ago
9

Evaluate the function. g(x) = 3x^2 – 2x + 5 Find f(2)​

Mathematics
1 answer:
Nadya [2.5K]3 years ago
3 0

Answer:

13

Step-by-step explanation:

Replace X with 2

Evaluate the function. g(x) = 3x^2 – 2x + 5 Find f(2)​

g(x) = 3(2)^2 – 2(2) + 5

Next conduct PEMDAS

Exponents are first so solve 2^2 which is 2 x 2 = 4

g(x) = 3(4) – 2(2) + 5

Next step is multiplication multiply 3 x 4 and 2x2

g(x) = 12 – 4 + 5

conduct adding and subtracting left from right

g(x) = 13

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Show that an integer is divisible by 11 if and only if the alternating sum (add first digit, subtract the second, add the third,
Bess [88]

Answer and Step-by-step explanation:

Suppose that we have a number y which is a positive integer and that:

y = x_n...x_5x_4x_3x_2x_1x_0

Where;

x_{0} = digit at 10⁰ => one's place (units place)

x_1 = digit at 10¹ => 10's place (tens place)

x_{2} = digit at 10² => 100's place (hundreds place)

x_{3} = digit at 10³ => 1000's place (thousands place)

.

.

.

x_{n} = digit at 10ⁿ place

Then;

y = x_{0} * 10⁰ + x_1 * 10¹ + x_{2} * 10² + x_{3} * 10³ + x_{4} * 10⁴ + x_5 * 10⁵ + . . . + x_{n} * 10ⁿ

<em>Since 10⁰ = 1, let's rewrite y as follows;</em>

y = x_{0}  + x_1 * 10¹ + x_{2} * 10² + x_{3} * 10³ + x_{4} * 10⁴ + x_5 * 10⁵ + . . . + x_{n} * 10ⁿ

Now, to test if y is divisible by 11, replace 10 in the equation above by -1. Since 10 divided by 11 gives -1 (mod 11)     [mod means modulus]

y = x_{0}  + x_1 * (-1)¹ + x_{2} * (-1)² + x_{3} * (-1)³ + x_{4} * (-1)⁴ + x_5 * (-1)⁵ + . . . + x_{n} * (-1)ⁿ

=> y =  x_{0}  - x_1 + x_{2} - x_{3} + x_{4} - x_5 + . . . + x_{n} (-1)ⁿ (mod 11)

Therefore, it can be seen that, y is divisible by 11 if and only if alternating sum of its digits x_{0}  - x_1 + x_{2} - x_{3} + x_{4} - x_5 + . . . + x_{n} (-1)ⁿ is divisible by 11

<em>Let's take an example</em>

Check if the following is divisible by 11.

i. 1859

<em>Solution</em>

1859 is divisible by 11 if and only if the alternating sum of its digit is divisible by 11. i.e if (1 - 8 + 5 - 9) is divisible by 11.

1 - 8 + 5 - 9 = -11.

Since -11 is divisible by 11 so is 1859

ii. 31415

<em>Solution</em>

31415 is divisible by 11 if and only if the alternating sum of its digit is divisible by 11. i.e if (3 - 1 + 4 - 1 + 5) is divisible by 11.

3 - 1 + 4 - 1 + 5 = 10.

Since 10 is not divisible by 11 so is 31415 not divisible.

3 0
4 years ago
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