All categories

3 years ago

Which of the following is the solution

Mathematics

2 answers:

Valentin [98]3 years ago

4 0

The smallest the absolute value will ever be is zero so the left side won't ever be smaller than -2 so won't ever be less than -3.

D. No solution

Margarita [4]3 years ago

4 0

Hey there!

Let's solve the inequality to find our answer

Firstly, lets add $2$ on each of your sides

Like: $|x| -2 +2 \leq -3 +2$

Cancel out the two $2's$ that's in front of the less than or equal to symbol ( $\leq$

Now we get: $|x| \leq -1$

So, since we got that result, your answer would be: $No\\ Solution$

(Not saying that that the answer would be always "no solution" because it won't)

Good luck on your assignment and enjoy your day!

~ $LoveYourselfFirst:)$

You might be interested in

Pls help me on number 5

Alekssandra [29.7K]

Answer is A trust me

7 0

2 years ago

Read 2 more answers

Find endpoint with given endpoint and midpoint

TEA [102]

Answer:

(21, 17 )

Step-by-step explanation:

Using the midpoint formula and equating to the coordinates of the midpoint.

Let endpoint 2 have coordinates (x, y ), then

0.5(x - 3) = 9 ( multiply both sides by 2 )

x - 3 = 18 ( add 3 to both sides )

x = 21

and

0.5(y - 5) = 6 ( multiply both sides by 2 )

y - 5 = 12 ( add 5 to both sides )

y = 17

endpoint 2 = (21, 17 )

3 0

3 years ago

Graph the line y=−3x+b if it is known that the graph goes through point:<br> b<br> B(5, 2)

egoroff_w [7]

Answer: y=-3x+17

b = 17

4 0

3 years ago

Be granted 10 points plus brainliest

BartSMP [9]

Answer:

8 square feet

Step-by-step explanation:

5 0

2 years ago

If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$

$xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}$

$xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}$

$xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)$

$\implies \boxed{xyz = x + y + z + 2}$

(C)

6 0

2 years ago