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2 years ago

a voulnteer evenly sorts 2750 ribbions into a 250 welcome bags. How many ribbions are in each welcome bag?

Mathematics

2 answers:

Savatey [412]2 years ago

6 0

Answer:

Step-by-step explanation:

2750/250 = 11

Kobotan [32]2 years ago

6 0

Answer: There are 11 ribbons in each bag.

Step-by-step explanation: Just divide 2750 by 250.

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Find derivative: ^6 square root x^5

SVEN [57.7K]

$\large\begin{array}{l} \textsf{Find the derivative of}\\\\ \mathsf{f(x)=\,^6\!\!\!\sqrt{x^5}}\qquad\qquad\textsf{(expressing it as a power...)}\\\\ \mathsf{f(x)=x^{\frac{5}{6}}} \end{array}$

$\large\begin{array}{l} \textsf{So you can use the power rule to differentiate it:}\\\\ \mathsf{f'(x)=\big(x^{\frac{5}{6}}\big)'}\\\\ \mathsf{f'(x)=\dfrac{5}{6}\,x^{\frac{5}{6}-1}}\\\\ \mathsf{f'(x)=\dfrac{5}{6}\,x^{\frac{5}{6}-\frac{6}{6}}} \end{array}$

$\large\begin{array}{l} \mathsf{f'(x)=\dfrac{5}{6}\,x^{\frac{5-6}{6}}}\\\\ \mathsf{f'(x)=\dfrac{5}{6}\,x^{-\,\frac{1}{6}}}\\\\ \mathsf{f'(x)=\dfrac{5}{6}\cdot \dfrac{1}{x^{\frac{1}{6}}}}\\\\ \mathsf{f'(x)=\dfrac{5}{6x^{\frac{1}{6}}}}\\\\\\ \boxed{\begin{array}{c}\mathsf{f'(x)=\dfrac{5}{6\,^6\!\!\!\sqrt{x}}} \end{array}}\qquad\checkmark \end{array}$

<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2154186</span>

$\large\textsf{I hope it helps. :-)}$

Tags: <em>derivative sixth root irrational function power rule differential calculus</em>

3 0

3 years ago

The length of the arc intercepted by a congruent central angle is proportional to the _______ in similar circles.

MissTica

Central angle is proportional to the central angle in similar circles

6 0

3 years ago

. 1−|3p+1|=−3! Thank you

inn [45]

Answer:

p = - $\frac{5}{3}$ , p = 1

Step-by-step explanation:

Given

1 - | 3p + 1 | = - 3 ( subtract 1 from both sides )

- | 3p + 1 | = - 4 ( multiply both sides by - 1 )

| 3p + 1 | = 4

The absolute value function always returns a positive value, however, the expression inside can be positive or negative, thus

3p + 1 = 4 OR - (3p + 1) = 4

Subtract 1 from both sides

3p = 3 ( divide both sides by 3 )

p = 1

- (3p + 1) = 4, that is

- 3p - 1 = 4 ( add 1 to both sides )

- 3p = 5 ( divide both sides by - 3 )

p = - $\frac{5}{3}$

As a check

Substitute these values into the left side of the equation and if equal to the right side then they are the solutions

p = 1 : 1 - | 3 + 1 | = 1 - |4| = 1 - 4 = - 3 ← true

p = - $\frac{5}{3}$ : 1 - | - 5 + 1 | = 1 - | - 4 | = 1 - 4 = - 3 ← true

Thus the solutions are p = 1, p = - $\frac{5}{3}$

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