Answer:
D)
Step-by-step explanation:
ASSUMING NORMAL DISTRIBUTION, LESS THAN 10% AT LOWER END
OF 15.34 MEANS [DENOTING MEAN BY M AND Standard Deviation. BY S]
M±AS=20%....................M-AS=15.34
FOR 20% LEVEL .......A=1.281........FROM TABLES
M-1.281×S=15.34............................1
SIMILARLY
M±BS=40%...................M+BS=16.31
FOR 40% LEVEL .............B=0.841...................FROM TABLES
M+0.841×S=16.31.............................2
EQN.2 - EQN.1
2.122×S=0.97
S=0.457=0.46
M=15.926= 15.93
HENCE, D IS THE ANSWER
that is D. μ = 15.93, σ =.46
Answer:
27 feet
Step-by-step explanation:
calculation using brain
Answer:
The answer is false
Step-by-step explanation:
In a sample above 30 obs like this the confidence interval is defined as
X+- t* (s/sqrt(n)) where X is the mean t the tvalue for a given confidence level, n the size of sample and s standar deviation.
To find de appropiate value of t we must see the T table where rows are degrees of freedom and columns significance level
The significance is obtained:
significance = 1 - confidence level = 1 - 0.9 = 0.10
Degrees of freedom (df) for the inteval are
df = n - 1 = 18 - 1 = 17
So we must look for the value of a t with 17 values and significance of 0.10 which in t table is 1.740 not 1.746 ( thats the t for 16 df)
Answer:
This is exponential growth
Step-by-step explanation:
The amount by which the function is increasing from point to point is increasing, so it must be a quadratic or exponential function. If it was a quadratic, the amount it increases by would be increasing by a steady amount. (Ex. x^2 increases by how much it increased the last time + 2). But because this is not what the data shows, the function must be exponential.
