hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -2 and b = 1 (Center at the A(-2,1))
r = AP......P( -4 , 1)
r² = (AP)²
r² = (4+2)² +(1-1)² = 36
an equation of the circle that satisfies the stated conditions.
Center at </span></span> A(-2,1), passing through P(-4, 1) is : (x+2)² +(y-1)² = 36
Answer:
24
Step-by-step explanation:
Answer:
x = -2
Step-by-step explanation:
5x + 2(x - 4) = 5x + x - 10
First, we need to to multiply out the parathesis in the equation:
5x + 2(x - 4) = 5x + x - 10
5x + 2x - 8 = 5x + x - 10
Next, we can combine "like terms" to simplify the equation further:
5x + 2x - 8 = 5x + x - 10
7x - 8 = 6x - 10
Now we can isolate the variable "x" to one side:
7x - 8 = 6x - 10
x - 8 = -10
x = -2
To check our work, we can replace x with -2 in our original equation:
5x + 2(x - 4) = 5x + x - 10
5(-2) + 2 (-2 - 4) = 5(-2) + -2 - 10
-10 + 2 (-6) = -10 -2 - 10
-22 = -22
I hope this helps!
-TheBusinessMan
Answer:
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