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hodyreva [135]
3 years ago
9

Which table represents a proportional relationship that has a constant of proportionality equal to 0.8?

Mathematics
1 answer:
garri49 [273]3 years ago
5 0

Answer:

correct answer is B

Step-by-step explanation:

hi

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Find the equation of the horizontal line passing through the point (-7 , -3)
Marta_Voda [28]

y = - 3

the equation of a horizontal line, parallel to the x- axis is y = c where c is the value of the y- coordinate the line passes through

Line passes through ( - 7, - 3) → y- coordinate is - 3

equation of line is y = - 3


4 0
3 years ago
The function f(x)=x^2 and its transformation f(x)=(x-k)^2 are shown below. What is the value of k?
Leto [7]

Answer:

<h2>f(x - k) = (x - k)²⇒ k = 5</h2>

Step-by-step explanation:

f(x) + n - shift the graph n units up

f(x) - n - shift the graph n units down

f(x - n) - shift the graph n units to the right

f(x + n) - shift the graph n units to the left

==============================================

Look at the picture.

The graph has been shifted 5 units to the right.

Therefore we have f(x - 5).

6 0
3 years ago
Dawson says that the expression (2 4/10+8 4/5(
Katen [24]

Answer:

56/5

Step-by-step explanation:

2 4/10=24/10

8 4/5=44/5

24/10+44/5=24/10+88/10=112/10=56/5

7 0
3 years ago
Dividing integers
Natasha2012 [34]

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.</em>

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.here,</em>

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.here,7. (-154) ➗ (-14) =11</em>

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.here,7. (-154) ➗ (-14) =1111. (-40) ➗10=-4</em>

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.here,7. (-154) ➗ (-14) =1111. (-40) ➗10=-415. 90 ➗ (-15)=-6</em>

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.here,7. (-154) ➗ (-14) =1111. (-40) ➗10=-415. 90 ➗ (-15)=-616. 108 ➗ (-9)=-12</em>

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.here,7. (-154) ➗ (-14) =1111. (-40) ➗10=-415. 90 ➗ (-15)=-616. 108 ➗ (-9)=-1217. (-48) ➗ (-6)=8</em>

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.here,7. (-154) ➗ (-14) =1111. (-40) ➗10=-415. 90 ➗ (-15)=-616. 108 ➗ (-9)=-1217. (-48) ➗ (-6)=818. (-105) ➗ 7=-15</em>

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.here,7. (-154) ➗ (-14) =1111. (-40) ➗10=-415. 90 ➗ (-15)=-616. 108 ➗ (-9)=-1217. (-48) ➗ (-6)=818. (-105) ➗ 7=-15hope it helps you......</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

8 0
3 years ago
Given that sin theta = 1/4, 0→theta→π/2, what<br>. what is the exact value of cos 8?​
natali 33 [55]
<h3>Answer: Choice B \frac{\sqrt{15}}{4}</h3>

===========================================================

Work Shown:

Angle theta is between 0 and pi/2, so this angle is in quadrant Q1.

Square both sides of the given equation

\sin \theta = \frac{1}{4}\\\\\sin^2 \theta = \left(\frac{1}{4}\right)^2\\\\\sin^2 \theta = \frac{1}{16}

Then use the pythagorean trig identity to get

\sin^2 \theta + \cos^2 \theta = 1\\\\\cos^2 \theta = 1-\sin^2 \theta\\\\\cos \theta = \sqrt{1-\sin^2 \theta} \ \ \ \text{cosine is positive in Q1}\\\\\cos \theta = \sqrt{1-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16}{16}-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16-1}{16}}\\\\\cos \theta = \sqrt{\frac{15}{16}}\\\\\cos \theta = \frac{\sqrt{15}}{\sqrt{16}}\\\\\cos \theta = \frac{\sqrt{15}}{4}\\\\

3 0
3 years ago
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