Answer:
i beleive it is c
Step-by-step explanation:
7/10=70/100=70%, so the answer is seventy-percent.
Answer:
x= 55 degrees
w = 5
Step-by-step explanation:
Triangle PQR contains two triangles, QPS and PSR.
Looking at triangle QPS, it is an isosceles triangle. This is shown by the two short lines that cuts line QP and line QS.
In an isosceles triangle, two sides and two angles are equal. The two equal angles are the base angles.
Therefore,
angle P and angle S are equal. Also
Line QP and line PS are equal. This means
6w - 10 = w
6w-w = 10
5w = 10
w = 10/2 = 5
Angle Q + 100 degrees = 180 ( sum of angles on a straight line)
Angle Q = 180 - 100 = 80 degrees
Angle Q = Angle S(base angles of an isosceles triangle)
Angle PSR = 180 - 80 = 100 degrees( sum of angles on a straight line is 180)
Angle PSR + x + 25 = 180
x = 180 - 25 - 100 = 55 degrees
Answer:
y = 4/3 x + 8/3
Step-by-step explanation:
A (-2; 0), B (6; 0) on circle circumference, circle center O (h , k) and radius r
(-2 - h)² + (0 - k)² = r²
(6 - h)² + (0 - k)² = r²
(-2 - h)² = (6 - h)²
4 + 4h + h² = 36 - 12h + h²
16h = 32 h = 2
the center on the line x + 2y + 4 = 0, ∴ 2 + 2y + 4 = 0
y = -3 i.e. k = -3 center O (2 , -3)
segment OA: (2 , -3) (-2 , 0)
slope OA = (-3 - 0) / (2 - (-2)) = -3 /4
tangent line through A (Lₐ) slope Lₐ = 4/3
y = mx + b for A(-2 , 0)
b = y - mx = 0 - (4/3 x (-2)) = 8/3
line tangent to the circumference at point A: y = 4/3 x + 8/3
6 + 2 < 9 + 3...u r correct