so the answer for this particular question is unknown because I havent done this course before
Answer:
i don't know this i think its 3.4 or 1.9
Answer:
a) r ⋀~p
b)(r⋀p)⟶q
c) ~r ⟶ ~q
d) (~p ⋀r) ⟶q
Step-by-step explanation:
To solve this question we will make use of logic symbols in truth table.
We are told that;
p means "The user enters
a valid password,”
q means “Access is granted,”
r means “The user has paid the
subscription fee”
A) The user has paid the subscription fee, but does not enter a valid
password.”
Fist part of the statement is correct and so it will be "r". Second part of the statement is a negation and will be denoted by ~p. Since both statements are joined together in conjunction, we will use the conjuction symbol in between them which is "⋀" Thus, we have; r ⋀~p
B) Still using logic symbols, we have;
(r⋀p)⟶q
⟶ means q is true when r and p are true.
C) correct symbol is ~r ⟶ ~q
Since both statements are negation of the question. And also, if ~r is true then ~q is also true.
D) Similar to answer A to C above, applying similar conditions, we have (~p ⋀r) ⟶q
Answer:
1/2
Step-by-step explanation:
(1/8+3/12)×(11/6-1/2)
Using bodmas
Deal with the bracket first and it should start with the addition
1/8+3/12
Lcm of the two is 96
12+24/96
=36/96
Then move to the next bracket
11/6-1/2
Lcm is 6
11-3/6
=8/6
Bring the two answers together
36/96×8/6
=1/2
