All of the above are true
1/sin^2x-1/tan^2x=
1/sin^2x-1/ (sin^2x/cos^2x)<<sin tan= sin/cos>>
= 1/sin^2x- cos^2x / sin^2x
= (1- cos^2x) / sin^2x <<combining into a single fraction>>
sin^2 x / sin^2x <<since 1- cos^2 x sin^2 x
=1
this simplifies to 1.
Answer:
Step-by-step explanation:
2(3x-1)+2(6)
6x-2+12
6x+10
Answer:
Beatrice will accumulate $1230.72 at the end of the year.
Step-by-step explanation:
We can write:

for deposits
The first month would have only the deposit reflected in her balance, then, expanding some steps of the calculation would yield:

A geometric series is given by:

Translating our series to the short form:

plugin in the values for the 12 month gives:

<span>Simplify (8 + 7i) + (2 –i)
</span>answer:10+6i