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3 years ago

13

Which input value produces the same output value for the two functions on the graph?

1 answer:

zheka24 [161]3 years ago

6 0

Answer:

X=3

Step-by-step explanation:

We have two linear functions which intersect at a point. Linear functions are lines which are made of points that satisfy the function or relationship. This means at the intersection, this point (3,-1), both functions have values. An input of x=3 produces y=-1 in both functions.

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A Scientist had a bottle that contains 56.6 mL of solution.She used 3.2 mL of the solution for an experiment.She poured half of

mario62 [17]

56.6 - 3.2 = 53.4
53.4 / 2 = 26.7
26.7 - 6 = 20.7ml
For the final answer she has 20.7ml of solution left.

Please mark as brainliest if you can

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3 years ago

Which is first X axis or Y axis?

Svetllana [295]

Answer:

You always do the X-axis first. Hope this helps! :)

<h3>CloutAnswers</h3>

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4 years ago

Read 2 more answers

Make a the subject of a2+b2=c2

wel

Answer:

$a=\sqrt{c^2-b^2$

⇒ $a=\sqrt{(c+b)(c-b)}$ [Factorized form]

Step-by-step explanation:

Given expression:

$a^2+b^2=c^2$

We need to make $a$ the subject.

In order to do that we need to solve the expression for $a$ in terms of $b$ and $c$

We have,

$a^2+b^2=c^2$

Subtracting both sides by $b^2$

$a^2+b^2-b^2=c^2-b^2$

$a^2=c^2-b^2$

Taking square root both sides in order to remove square of $a$

$\sqrt{a^2}=\sqrt{c^2-b^2}$

$a=\sqrt{c^2-b^2$

The difference of squares can be factorized and written as:

$a=\sqrt{(c+b)(c-b)}$ [difference of squares $x^2-y^2=(x+y)(x-y)$ ]

4 0

3 years ago

Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a

Mashutka [201]

Answer:

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

Step-by-step explanation:

Given

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Required

Make the denominator equal

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Factorize the denominator

$\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}$

$\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}$

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

$\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}$

$\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}$

$\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}$

<em>The expression now have the same denominator</em>

7 0

3 years ago

The length of a rectangle is one inch less than three times its width. If the perimeter of the rectangle is 54 inches, find the

CaHeK987 [17]

w - width

3w - 1 - length

54 in - perimeter

w + w + (3w - 1) + (3w - 1) = 8w - 2 - perimeter

The equation:

8w - 2 = 54 <em>add 2 to both sides</em>

8w = 56 <em>divide both sides by 8</em>

w = 7

3w - 1 = 3(7) - 1 = 21 - 1 = 20

<h3>Answer: The length = 20 in.</h3>

7 0

3 years ago