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Alla [95]
3 years ago
5

Unit 3: Parallel & Perpendicular Lines Homework 5: Linear Equations Slope-Intercept & Standard Form

Mathematics
1 answer:
Alona [7]3 years ago
4 0
And you can see that I don’t have respect you don’t deserve that you
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If the m∠2 = 40, what is the m∠5?
77julia77 [94]

Answer: The answer is 100.

Step-by-step explanation: 40 divided by 2 = 20

x=20

20x5=100

5 0
4 years ago
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Help me with which triangle it is and how do I find x?
3241004551 [841]

Answer:

isosceles

x=14

Step-by-step explanation:

isosceles because of the two I symbols on the triangle

x+5=2x-9

5+9=2x-x

14=x

6 0
3 years ago
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If (x-1)/(x)=20 then x=
nadezda [96]
D:x\neq0\\\\\frac{x-1}{x}=20\ \ \ \ |cross\ multiply\\\\20x=x-1\ \ \ \ |subtract\ x\ from\ both\ sides\\\\19x=-1\ \ \ \ \ \ |divide\ both\ sides\ by\ 19\\\\\boxed{x=-\frac{1}{19}}

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3 years ago
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Circle U is shown. Chords R T and Q S intersect at a point forming 4 angles. The top left angle is angle 1, and the top right an
Dima020 [189]

Based on the calculations, the measures of angles 1 and 2 are 50° and 135° respectively.

<h3>What is the theorem of intersecting chord?</h3>

The theorem of intersecting chord states that when two (2) chords intersect inside a circle, the measure of the angle formed by these chords is equal to one-half (½) of the sum of the two (2) arcs it intercepts.

By applying the theorem of intersecting chord to circle U shown in the image attached below, we can infer and logically deduce that angle 1 will be given by this formula:

m∠1 = ½(53 + 47)

m∠1 = ½(100)

m∠1 = 50°.

Since angles 1 and 2 are linear pair, they are supplementary angles. Thus, we have:

m∠1 + m∠2 = 180°

m∠2 = 180 - m∠1

m∠2 = 180 - 50

m∠2 = 130°.

Read more on intersecting chords here: brainly.com/question/27251228

#SPJ1

6 0
2 years ago
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The product of two mixed numbers x and y is 10. If x= _ 2/3 and y=_ 3/4 ,<br> find x and y?
Akimi4 [234]

Answer:

  • x = 2 2/3
  • y = 3 3/4

Step-by-step explanation:

There may be other ways to do this. Here's the approach I took. Let the integer part of x be represented by "a", and the integer part of y be represented by "b". Now, we have ...

  (a +2/3)(b +3/4) = 10

Multiplying by 12, this becomes ...

  (3a +2)(4b +3) = 120

There are only 16 divisors of 120, so they can be easily enough checked one at a time.

  120 = 1·120 = 2·60 = 3·40 = 4·30 = 5·24 = 6·20 = 8·15 = 10·12

Of these divisors, the ones that are of the form 3a+2 are ...

  2, 5, 8, 20 . . . . a=0, 1, 2, 6

The ones that are of the form 4b+3 are ...

  3, 15 . . . . b = 0, 3

The factor pair that consists of a number on the first list and a number on the second list is ...

  120 = 8·15

corresponding to a=2 and b=3. So, the mixed numbers you want are ...

  x = 2 2/3

  y = 3 3/4

_____

<em>Check</em>

  (2 2/3)·(3 3/4) =2·3 +2·3/4 +2/3·3 +2/3·3/4 = 6 +6/4 +2 +2/4 = 8+8/4 = 10

6 0
3 years ago
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