To solve this problem you must apply the proccedure shown below:
1. You have the following parent function given in the problem above:
2. If you want to shift this parent function up six units, you only have the add a , then, you will obtain the following new function:
Therefore, as you can see, the answer is:
The 90% confidence interval for the true difference between the population proportions is [ - 0.0908, - 0.0092]
Given,
= 731
= 644
= 0.33
= 0.28
z score for 90% confidence interval = 1.645
Here, the confidence interval formula :
( ) ± z
Substituting the values, we get
(0.33 - 0.28) ± 1.645
= 0.05 ± 1.645
= 0.05 ± 1.645
= 0.05 ± 1.645 × 0.0248093914
= 0. 05 ± 0.0408114489
Confidence interval:
- 0.05 - 0.0408114489 = - 0.0908114489 ≈ - 0.0908
- 0.05 + 0.0408114489 = - 0.0091885511 ≈ - 0.0092
The confidence interval for the true difference between the population proportions is [ - 0.0908, - 0.0092]
Learn more about confidence interval here:brainly.com/question/17421912
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