Ask question

Ask question

All categories

3 years ago

5

dog's food bowl holds 3 cups of dog food. Tim uses a scoop that holds 1/4 of a cup of dog food. how many scoops will it take for

Timothy to fill the dog bowl?

1 answer:

Setler79 [48]3 years ago

6 0

Answer:

12 scoops

Step-by-step explanation:

4 scoops = 1 cup

8 scoops = 2 cups

12 scoops = 3 cups

You might be interested in

I need help on math

Viefleur [7K]

Answer:

its the first one

Step-by-step explanation:

i have no step by step explanation

7 0

2 years ago

A rocket was launched and its height, h, in metres, above the ground after time,

Marianna [84]

Short answer b 7m

Very simple just do the math mostly multiplying

6 0

3 years ago

What is the value of k in the equation below

Dima020 [189]

Answer:

<h2>4</h2>

Step-by-step explanation:

5k-2k=12

3k=12

k=4

5 0

3 years ago

Can somebody help me with this. Will mark brainliest!

alexandr402 [8]

Answer:

The length of FG is 2.

Step-by-step explanation: B and F are the same point, just reflected, so BC=FG.

7 0

3 years ago

Listed below are speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, California (based on data from SigAlert

adell [148]

Answer:

Option (B) is the correct answer to the following question.

Step-by-step explanation:

Step-1: We have to find the Mean of the series.

The series is Given in the question 62 61 61 57 61 54 59 58 59 69 60 67.

$Mean(\overline{x})=\frac{62+61+61+57+61+54+59+58+59+69+60+67}{12}$ $= 60.67$

Step-2: We have to find the Standard Deviation.

Let Standard Deviation be x.

Formula of Standard Deviation is: $s= \sqrt{\frac{\sum(x_{i}+\overline{x})}{n-1}}$

Put value in formula of Standard Deviation,

$s= \sqrt{\frac{(62+60.67)^{2}+(61+60.67)^{2}+(61+60.67)^{2}+(57+60.67)^{2}+....(67+60.67)^{2}}{n-1}}$ = 40.75

Step-3: Then, we have to find the critical value by chi-square.

$X_{1-\alpha/2}^{2}=3.82$

$X_{1-\alpha/2}^{2}=21.92$

Then, find the confidence interval which is 95%.

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{21.92}.(4.075)^2 }\approx2.8868 \\ i.e 2.9$

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{3.816}.(4.075)^2 }\approx6.9188 \\ i.e 6.9$

5 0

3 years ago