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lina2011 [118]
3 years ago
14

The number of 8-ounce glasses of water Shane drank each day for 12 days is represented in

Mathematics
1 answer:
masha68 [24]3 years ago
5 0

The histogram representing the data is attcwhwd in the picture below.

Answer:

C On exactly 25% of these days, Shane drank 3 to 4 glasses of water.

Step-by-step explanation:

The number of 8 - ounce glasses is represented on the x - axis and the number of days on the y - axis.

From the histogram ;

Shane drank 1 - 2 glasses on exactly 1 day

Shane drank 3 - 4 glasses on exactly 3 days

Shane drank 5 - 6 glasses on exactly 6 day

Total number of days = 12

60% of 12 = 7.2

On exactly 60% of the days, which is 7.2 days, number of glasses drunk isn't covered by the histogram

25% of 12 ; 0.25 * 12 = 3 days

From the histogram, number of glasses consumed is 3 - 4 glasses ; which is the only true statement about the histogram in the options given.

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tia_tia [17]

Answer:

El período paleolítico corresponde a \frac{332}{333} de la época prehistórica.

Step-by-step explanation:

En primer lugar, se determina la extensión de tiempo, medida en años, tanto de la época prehistórica como el período paleolítico: (Nótese que el signo negativo significa a.C.)

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\Delta T = -2500-(-2500000)

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\Delta t = -10000 - (-2500000)

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La fracción de la época prehistórica que corresponde al período paleolítico es:

r = \frac{\Delta t}{\Delta T}

r = \frac{2490000\,years}{2497500\,years}

r = \frac{332}{333}

El período paleolítico corresponde a \frac{332}{333} de la época prehistórica.

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3 years ago
Help find the missing lengths round to nearest tenth
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Answer:

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Step-by-step explanation:

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SOH - CAH - TOA

Since the opposite side is given and we need to find the length of the adjacent side, we can use tangent to solve for x.

tan 21=\frac{opposite}{adjacent} \\tan 21 =\frac{8}{x} \\0.384 =\frac{8}{x} \\0.384x =8 \\x=\frac{8}{0.384} \\x=20.84

Since the opposite side is given and we need to find the length of the hypotenuse, we can use sine to solve for y.

sin 21=\frac{opposite}{hypotenuse} \\sin21 =\frac{8}{y} \\0.358 =\frac{8}{y} \\0.358y=8 \\y=\frac{8}{0.358} \\y=22.32

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  \dfrac{x^2-16x+64}{4x^2-36x+32}=\dfrac{(x-8)^2}{4(x-8)(x-1)}=\boxed{\dfrac{x-8}{4x-4}}

The function is undefined for x=1 and x=8, the values of x that make the original denominator zero.

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