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BigorU [14]
2 years ago
9

The rectangular floor of a classroom is 20 feet in length and 36 feet in width. A scale

Mathematics
2 answers:
vova2212 [387]2 years ago
5 0

Answer:

56

Step-by-step explanation:

20 feet =10 inchs

10 feet is 5 inches

5 feet is 2.5 inches

1 feet is 0.5 inch

10+5+2.5+0.5= 18 inches

10+10+18+18=56

marusya05 [52]2 years ago
4 0
Your answer is 56 hopefully this helps
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**Solve by Elimination<br> 3 + 2x - y = 0<br> -3-7y = 10x<br> 7) x =<br> 8) y =
timofeeve [1]
Answer:

Explanation:

3 + 2x - y = 0
Or 2x - y = -3 (1)

-3-7y = 10x
Or -10x - 7y = 3 (2)

2x - y = -3 (1)
-10x - 7y = 3 (2)
———————

Multiply 5 to (1)

5(2x - y = -3)
-10x - 7y = 3
———————
10x - 5y = -15
-10x - 7y = 3
———————
-12y = -12
y = -12/-12
y = 1

Plug y value in (1)

2x - 1 = -3
2x = -3 + 1
2x = -2
x = -2/2 = -1

Therefore, x = -1 and y = 1
7 0
2 years ago
Find the value of X in the triangle.<br><br> Please explain. Thanks.
Anna [14]
29°

triangles can only have 180°

This is a right triangle, so one angle is 90°, leaving us with 90° left

90°-61°= 29°
4 0
3 years ago
Read 2 more answers
The circumference of a globe is 16pi inches. what is the volume of the globe? show your work. use 3.14 for pi ​
docker41 [41]

Answer:

v=2144.66

Step-by-step explanation:

formula: 4/2 (pi) (r)³

................

3 0
2 years ago
Read 2 more answers
Which expression is equivalent to −10+(−40)+(−90) ?
Igoryamba
The answer is D because -10+(-40)+(-90) is the same just swiched
8 0
3 years ago
Read 3 more answers
HELPP!!
SSSSS [86.1K]

Answer:

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

7 0
3 years ago
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