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BigorU [14]
3 years ago
9

The rectangular floor of a classroom is 20 feet in length and 36 feet in width. A scale

Mathematics
2 answers:
vova2212 [387]3 years ago
5 0

Answer:

56

Step-by-step explanation:

20 feet =10 inchs

10 feet is 5 inches

5 feet is 2.5 inches

1 feet is 0.5 inch

10+5+2.5+0.5= 18 inches

10+10+18+18=56

marusya05 [52]3 years ago
4 0
Your answer is 56 hopefully this helps
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tammy is 14 years old. she has a younger sister and an older brother. her sister is 12. the mean of all their ages is 14. how ol
mafiozo [28]

Answer:

16

Step-by-step explanation:

To solve, we can use an equation finding the average of the siblings'ages.

\frac{14 + 12 + x}{3}  = 14 \\  \ 14 + 12 + x = 42 \\ x = 42 - 14 - 12 \\ x = 16

7 0
3 years ago
Please help I will give brainliest if you are right
Vsevolod [243]

Answer:

I believe its A im not exactly sure though

4 0
3 years ago
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Given vectors u = ⟨2, –3⟩ and v = ⟨1, –1⟩, what is the measure of the angle between the vectors?
oksano4ka [1.4K]

Answer:

The measure of the angle between the vectors = Ф = 11.30°

Step-by-step explanation:

Given

  • u = ⟨2, –3⟩
  • v = ⟨1, –1⟩

\mathrm{Computing\:the\:angle\:between\:the\:vectors}:\quad \cos \left(\theta \right)\:=\frac{\vec{a\:}\cdot \vec{b\:}}{\left|\vec{a\:}\right|\cdot \left|\vec{b\:}\right|}

Next, find the lengths of the vectors:

\mathrm{Computing\:the\:Euclidean\:Length\:of\:a\:vector}:\quad \left|\left(x_1\:,\:\:\ldots \:,\:\:x_n\right)\right|=\sqrt{\sum _{i=1}^n\left|x_i\right|^2}

u = ⟨2, –3⟩

\:\:\left|u\right|\:=\sqrt{2^2+\left(-3\right)^2}

     =\sqrt{13}

u = ⟨2, –3⟩

|v|=\sqrt{1^2+\left(-1\right)^2}

    =\sqrt{2}

Finally, the angle is given by:

\mathrm{Computing\:the\:angle\:between\:the\:vectors}:\quad \cos \left(\theta \right)\:=\frac{\vec{a\:}\cdot \vec{b\:}}{\left|\vec{a\:}\right|\cdot \left|\vec{b\:}\right|}

cos (Ф) = 5/√26

Ф = arc cos (cos (Ф)) = arc cos (5 √26) / (26)

Ф = 11.30°

Thus, the measure of the angle between the vectors = Ф = 11.30°

6 0
3 years ago
Read 2 more answers
11^-5 ÷ 11^-3 please help!!!!​
prohojiy [21]

Answer:

Step-by-step explanation:

a^{-m}=\frac{1}{a^{m}}\\\\Therefore, \frac{1}{a^{-m}}=a^{m}

11^{-5} ÷ 11^{-3} = 11^{-5} * 11^{3}\\\\            {a^{m}*a^{n} = a^{m+n}  }

                   11^{-5+3} \\\\= 11^{-2}

                 

6 0
3 years ago
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PLEASE HELP <br> Which graph represents the function f(x)=0.2x+3?
Mandarinka [93]

Answer:

top right, the one you currently have selected

4 0
3 years ago
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