Nickel-63 has half-life of about 96 years. after 336 years,about how many milligrams of an 800 mg sample will remain?
2 answers:
F=ar^t if the half-life is 96 years... .5=r^96 ln(.5)=96lnr ln(.5)/96=lnr r=e^((ln.5)/96) f=800e^(336(ln.5)/96) f=70.71 So about 71mg will remain after 336 years.
Answer:
71 mg
Step-by-step explanation:
nickel-63 has half-life of about 96 years. after 336 years
Initial value is 800 mg sample
half life of nickel-63 is 96 years
time given is 336 years
we use half life formula to get the71 mg amount of nickel remains
Final value = initial value (1/2)^(Time /t(half life ))
now simplify it
336/ 96 = 7/2
= 70.7106
so answer is
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