Question

Nickel-63 has half-life of about 96 years. after 336 years,about how many milligrams of an 800 mg sample will remain?

Answer 1

F=ar^t if the half-life is 96 years...

.5=r^96

ln(.5)=96lnr

ln(.5)/96=lnr

r=e^((ln.5)/96)

f=800e^(336(ln.5)/96)

f=70.71

So about 71mg will remain after 336 years.

Answer 2

Answer:

71 mg

Step-by-step explanation:

nickel-63 has half-life of about 96 years. after 336 years

Initial value is  800 mg sample

half life of nickel-63 is 96 years

time given is 336 years

we use half life formula to get the71 mg amount of nickel remains

Final value = initial value (1/2)^(Time /t(half life ))

$final \ value = 800(\frac{1}{2})^{\frac{336}{96}}$

now simplify it

336/ 96 = 7/2

$final \ value = 800(\frac{1}{2})^{\frac{7}{2}}$

= 70.7106

so answer is