You can use the <u>determinant</u><u> (square root)</u> of a quadratic equation to determine the number and type of solutions of the equation.
> 0 → 2 real solutions
= 0 → 1 real solution (double root)
< 0 → 2 imaginary(complex) solutions
Answer:
f (-2)=5×-2+4
= -10+4
= -6
f (3)=5×3+4
=15+4
=19
f (5)=5×5+4
25+4
=29
only the mean
Step-by-step explanation:
The mean which by where you add all of the data 6+7+9+10+11+13+14/7 Equals 10 which is the middle value, making it the measure of center
-10
so,a=-10