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creativ13 [48]
4 years ago
10

You can use the what of a quadratic equation to determine the number and type of solutions of the equation?

Mathematics
1 answer:
adoni [48]4 years ago
3 0

You can use the <u>determinant</u><u> (square root)</u> of a quadratic equation to determine the number and type of solutions of the equation.

\sqrt{b^{2}-4ac} > 0    → 2 real solutions

  • if \sqrt{b^{2}-4ac} is a perfect square, then rational sol'ns
  • if \sqrt{b^{2}-4ac} is not a perfect square, then irrational sol'ns

\sqrt{b^{2}-4ac} = 0    → 1 real solution (double root)

\sqrt{b^{2}-4ac} < 0    → 2 imaginary(complex) solutions

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A jar contains 30 red, 40 blue, and 50 white buttons, you pick one button at random, find the probability that it is red or blue
Oksanka [162]

Answer:

70/120=58.333%

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30+40+50=120

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70/120

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3 years ago
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(6) (Bonus) Determine the Cartesian equation of the surface with spherical coordinate equation rho = 2 cos θ sin φ − 2 sin θ sin
KonstantinChe [14]

Answer:

Hence, the sphere has a radius of \sqrt{3}  and is centered at the point (1,-1,1)

Step-by-step explanation:

We have the equation

\rho=2cos\theta cos\phi-2sin\theta sin\phi+2cos\phi

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\rho=\sqrt{x^2+y^2+z^2}\\x=\rho cos\theta sin\phi\\y=\rho sin\theta sin\phi\\z= \rho cos\phi

by substituting we have:

\rho=2[\frac{x}{\rho}-\frac{y}{\rho}+\frac{z}{\rho}]\\\\\rho^2=2x-2y+2z\\\\x^2+y^2+z^2=2x-2y+2z

We have to complete squares:

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Hence, the sphere has a radius of \sqrt{3}  and is centered at the point (1,-1,1)

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4 0
3 years ago
If 20% of a number p is 10, what is 10% of p?
kobusy [5.1K]

Answer:

5

Step-by-step explanation:

20% of p = 10

20% = 0.2

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Multiply both sides of the equation by 5

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Find 10% of p

10% = 0.1

Multiply

0.1(50)

5

10% of p is 5

Hope this helps :)

8 0
3 years ago
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