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stepladder [879]
3 years ago
5

In ΔXYZ and ΔEFG, angles Y and F are right angles. Which set of congruence criteria would be enough to establish that the two tr

iangles are congruent by HL?
A.
XZ ≅ EG and ∠X ≅ ∠E
B.
XZ ≅ EG and YZ ≅ FG
C.
XZ ≅ FG and ∠X ≅ ∠E
D.
XY ≅ EF and YZ ≅ FG
Mathematics
1 answer:
alexandr1967 [171]3 years ago
7 0

Answer:

I think it is B.

Step-by-step explanation:

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What is 3/4 improper or proper or mixed
kotegsom [21]

Answer:

proper because the numerator is lower than the denominator

3 0
3 years ago
Billy has a die. He rolls the die, and if the result is not even, he rolls the die
PIT_PIT [208]

Answer:

1/4 is the answer.

Step-by-step explanation:

If he has a die then it is 6 sided. He has a 1/2 chance the 1st time that he gets a non-even number. The next time he also has a 1/2 chance of getting an even number so it's 1/2 times 1/2 = 1/4.

4 0
2 years ago
The graph below represents which system of inequalities?
attashe74 [19]

Answer:

y ≤ 2x -2 Option C.

Step-by-step explanation:

Equation of the dotted line which passes through (3,0) and (0,8) will be

y = mx+C

m = \frac{y-y'}{x-x'}=\frac{3-0}{0-3} = -1

and C = 3

So equation will be y = x + 3

But shaded blue part is above the dotted line so inequality will be y> -x +3

Equation of the second solid line which passes through ( 0,-2) and (1,0) will be

y = mx + C

m = \frac{y-y'}{x-x'} = \frac{0+2}{1-0} = 2

and C = -2

So equation of the line will be y = 2x - 2

But shaded yellow part is below the solid line.

So inequality will be

y ≤ 2x -2

Option C. is the answer.

5 0
2 years ago
​together, steve and tom sold 7777 raffle tickets for their school. steve sold 1414 more than twicetwice as many raffle tickets
storchak [24]
Steve = S , Tom = T
1) S+T = 7777
2) S= 1414 + 2T

put 2) in 1)

1414+2T + T = 7777
1414 +3T = 7777
3T = 6363
so T = 2121
then Steve sold 1414+2(2121) = 1414+4242=5656 tickets
while Tom sold 2121 tickets
5 0
3 years ago
If triangles have the ratio of 2:3 adn the smaller traingle has a aside length of 7 what si length of the correspodning sides
REY [17]
2:3=7:x\\\\\dfrac{7}{x}=\dfrac{2}{3}\ \ \ \ |cross\ multiply\\\\2x=7\cdot3\\\\2x=21\ \ \ |:2\\\\\boxed{x=10.5}
5 0
3 years ago
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