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stepladder [879]
3 years ago
5

In ΔXYZ and ΔEFG, angles Y and F are right angles. Which set of congruence criteria would be enough to establish that the two tr

iangles are congruent by HL?
A.
XZ ≅ EG and ∠X ≅ ∠E
B.
XZ ≅ EG and YZ ≅ FG
C.
XZ ≅ FG and ∠X ≅ ∠E
D.
XY ≅ EF and YZ ≅ FG
Mathematics
1 answer:
alexandr1967 [171]3 years ago
7 0

Answer:

I think it is B.

Step-by-step explanation:

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Obviously a b c & d.
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Graph a line that contains the point (-5,-3) and has a slope of -2
Tpy6a [65]

Answer:

-->

Step-by-step explanation:

Graph (-5,-3) and use the slope, -2, to find another point. -2 can also be written as -\frac{2}{1}

\frac{rise}{run} =\frac{-2}{1} and  \frac{rise}{run} =\frac{2}{-1} **

Use both. This works because either way, they will lie on the same line with the same slope. So, starting at (-5,-3), go down two points (-)* and to the left 1 (+)*, then, starting at (-5,-3) again, go up two points (+)* then to the right 1 point (-)*.

* If the number is negative, you either go down or to the right. If the number is positive, you go up and to the left.

**Rise over run refers to the change in the y-axis and the change in the x-axis: \frac{rise}{run} =\frac{y-axis}{x-axis}. Only one number is negative because, if both were negative, that would make a positive number, but the slope is -2, not 2.

Another way you could do this is by finding points first. All you need to do is turn the slope into a "point". Remember, 2 is the y and 1 is the x:

-2=-\frac{2}{1} = (1,-2) and (-1,2)

Then, using (-5,-3) and your new points, add them separately:

(-5,-3)+(1,-2)\\(-5+1,-3+(-2))\\(-5+1,-3-2)\\(-4,-5)

(-4,-5) is one point

(-5,-3)+(-1,2)\\(-5+(-1),-3+2)\\(-5-1,-3+2)\\(-6,-1)

(-6,-1) is another point. Connect the three points. You can check your work on the graph:

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Which of the following ordered pairs is a solution of X+1/2y=1
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4 years ago
Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and 1 red marbles. Find the following probabilities of Mirand
kvasek [131]

Answer:

(a)\frac{5}{7},\frac{1}{6} (b)\frac{1}{7},\frac{1}{6} (c)\frac{5}{7},\frac{2}{3},\frac{3}{5}

Step-by-step explanation:

GIVEN: Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and

TO FIND: a) A Blue, then a red Preview

,b)A red, then a white Preview

,c) A Blue, then a Blue, then a Blue.

SOLUTION:

Total marbles in bag =7

(a)

Probability of drawing blue marble =\frac{\text{total blue marble}}{\text{total marbles}}

                                                          =\frac{5}{7}

As marble is not returned to bag,

Probability of drawing red marble  =\frac{\text{total red marble}}{\text{total marbles}}

                                                         =\frac{1}{6}

(b)

Probability of drawing red marble =\frac{\text{total red marble}}{\text{total marbles}}

                                                          =\frac{1}{7}

As marble is not returned to bag,

Probability of drawing white marble  =\frac{\text{total white marble}}{\text{total marbles}}

                                                         =\frac{1}{6}

(c)

Probability of drawing blue marble =\frac{\text{total blue marble}}{\text{total marbles}}

                                                          =\frac{5}{7}

As marble is not returned to bag,

Probability of drawing second blue marble  =\frac{\text{total blue marble}}{\text{total marbles}}

                                                                         =\frac{4}{6}=\frac{2}{3}

As marble is not returned to the bag

Probability of drawing third blue marble   =\frac{\text{total blue marble}}{\text{total marbles}}

                                                                    =\frac{3}{5}

8 0
3 years ago
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