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timurjin [86]
3 years ago
11

I need help plzz its due TODAYYY

Mathematics
1 answer:
kobusy [5.1K]3 years ago
3 0

Answer:

1st box: Asso. prop= m+(4+x)

2nd box: Comm. Prop= m+4=4+m

3rd box: iden. prop= m+0=m

4th box: Zero prop: m x 0=0

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Georgia [21]
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Step-by-step explanation:

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3 years ago
HELP!
maksim [4K]

<u>Part A</u>

<u />4x^2 -7x-15=0\\\\(4x+5)(x-3)=0\\\\x=-\frac{5}{4}, 3

So, the x-intercepts are \boxed{\left(-\frac{5}{4}, 0 \right), (3,0)}

<u>Part B</u>

The vertex will be a minimum because the coefficient of x^2 is positive.

The x-coordinate of the vertex is x=-\frac{-7}{2(4)}=\frac{7}{8}

Substituting this back into the function, we get f\left(\frac{7}{8} \right)=4\left(\frac{7}{8} \right)^2 -7\left(\frac{7}{8} \right)^2 -15=-\frac{289}{16}

So, the coordinates of the vertex are \boxed{\left(\frac{7}{8}, -\frac{289}{16} \right)}

<u>Part C</u>

Plot the vertex and the x-intercepts and draw a parabola that passes through these three points.

The graph is shown in the attached image.

7 0
2 years ago
And outdoor deck is 7 feet wide. The perimeter of the deck is 64 feet. What is the length of the deck?
vova2212 [387]
Well perimeter is lengthx2 and widthx2 so   7x2=14 
then 64-14=50
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length=25
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