Ask question

Ask question

All categories

2 years ago

6

Proving the Converse of the Parallelogram Side Theorem

1 answer:

Brrunno [24]2 years ago

6 0

Answer:

do it yourself

Step-by-step explanation:

You might be interested in

Dara has to solve 35 math problems for homework. She has completed 14 of them.what fraction of the problems does she have left t

RSB [31]

Answer: 3/5

Step-by-step explanation: thats your answer.

6 0

3 years ago

garri49 [273]

I'm pretty sure it would be <span>x - y + 1 = 0 because if you plug in one of the coordinates into each equation, this is the only one that works.

</span><span>y - x + 1 = 0
2 - 1 + 1 = 0
2 = 0 not correct

</span><span>x - y + 1 = 0
1 - 2 + 1 = 0
0 = 0 correct

</span><span>-x - y + 1 = 0
-1 - 2 + 1 = 0
-2 = 0 not correct
</span>

4 0

3 years ago

PLS I need help, this is due today. thank u.

mariarad [96]

Here, you would complete it with the Pythagorean Theorem.

So, A^2 + B^2 = C^2

So 14^2 + B^2 = 14^2

This equals = B = 11.49

6 0

3 years ago

Read 2 more answers

How many 10 kobo coins are there in #9.90?

baherus [9]

Answer:

99

Step-by-step explanation:

1₦ = 100 k

₦9.90 =?

=990k

990/10=99

4 0

2 years ago

In how many ways can 6 competitors finish a race assuming there are no ties?In how many ways can we sit n people on r < n cha

VLD [36.1K]

Answer: a) 720, b) $^nC_r=\dfrac{n!}{(n-r)!r!}$ c) 336, d) 30240 e) 120.

Step-by-step explanation:

Since we have given that

a) Number of competitors = 6

We need to find the number of ways that 6 competitors can finish a race and there are no ties.

So, Number of ways would be

$6!=720$

b) number of people = n

Number of chairs = r (r<n)

so, the number of ways we can sit n people on r<n chairs is given by

$^nC_r=\dfrac{n!}{(n-r)!r!}$

c) If there are three awards :

Gold, silver, bronze.

We need to find the number of ways that these medals can be awarded.

Number of ways is given by

$^8P_3\\\\=336$

d) Number of 5-digit zip codes are possible is given by

$^{10}P_5=30240$

e) Number of poeple = 10

Number of people required in committee = 3

Number of different 3 person committee that are selected from 10 people is given by

$^{10}C_3=120$

Hence, a) 720, b) $^nC_r=\dfrac{n!}{(n-r)!r!}$ c) 336, d) 30240 e) 120.

6 0

3 years ago