Given line y-1/6x+9,find a perpendicular line to the given line passes through points (6,-3)?

Mathematics

1 answer:

DerKrebs [107]3 years ago

7 0

Answer:

y + 3 = (6)(x - 6)

Step-by-step explanation:

The proper format for this equation y-1/6x+9 is y = (-1/6)x+9.

Any line perpendicular to y = (-1/6)x+9 has the slope which is the negative reciprocal of that of y = (-1/6)x+9, or the negative reciprocal of -1/6. That is +6.

Thus, the desired line, which passes through (6, -3), is found using the point-slope formula for the equation of a straight line:

y + 3 = (6)(x - 6)

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