C is the answer ! Hope I’m correct
Given:
μ = 89 ng/ml, population mean
σ = 23 ng/ml, population standard deviation
Random variable, x = 100
To test P(x < 100), calculate the z-score.
z = (x-μ)/σ = (100 - 89)/23 = 0.4783
From standard tables, obtain
P(x < 100) = 0.6838 = 68.4%
Answer: 68.4%
Answer:
..............
...............
Step-by-step explanation:
Simplify: 40y^3 - 8y^2 + 16y/8 y^2
40y^3 + -8y^2 + 2y^3
Combine terms: 40y^3 + -8y^2 + 2y^3
(40y^3 + 2y^3) + (-8y^2)
Answer: 42y^3 + -8y^2
