All categories

2 years ago

Henry ran 1 5/8 miles in the morning and 9/10 miles in the afternoon how many miles did he run in all

Mathematics

2 answers:

Semmy [17]2 years ago

8 0

Answer:

101/40 miles or 2 21/40

Step-by-step explanation:

You add the two values together.

kolezko [41]2 years ago

7 0

Answer:

2 21/40

Step-by-step explanation:

You might be interested in

Kathy dropped a snowball from a building that is 39.2 meters tall. The equation t2 = 39.29.8 represents the amount of time, in s

DIA [1.3K]

Answer:

We note that the equation that is compatible with the given equation is the kinematic equation of free fall where;

t² = 39.2 × 2/9.81

From which we have;

The time it takes the snowball to reach the ground is approximately 2.83 seconds

Step-by-step explanation:

The height of the building from which the ball is dropped, h = 39.2 m

The equation of the dropped a snowball, is given as follows;

t² = 39.2 × 9.8

Using the From the equation of free fall, we have;

s = u·t + 1/2·g·t²

Where;

u = The initial velocity = 0 m/s

t = The time of flight

g = The acceleration due to gravity = 9.81 m/s²

Therefore, we get;

∴ s = The height from which the snowball is dropped = 39.2 m

Therefore, we get;

39.2 = 0×t + 1/2×9.81×t²

∴ t² = 39.2 × 2/9.81 ≈ 7.99

t = √(7.99) ≈ 2.83

The time it takes the snowball to reach the ground, t ≈ 2.83 s.

8 0

2 years ago

An education researcher claims that 58% of college students work year-round. In a random sample of 400 college students, 232

Hatshy [7]

Answer:

The proportion of college students who work year-round is 58%.

Step-by-step explanation:

The claim made by the education researcher is that 58% of college students work year-round.

A random sample of 400 college students, 232 say they work year-round.

To test the researcher's claim use a one-proportion z-test.

The hypothesis can be defined as follows:

H₀: The proportion of college students who work year-round is 58%, i.e. p = 0.58.

Hₐ: The proportion of college students who work year-round is 58%, i.e. p ≠ 0.58. C

Compute the sample proportion as follows:

$\hat p=\frac{232}{400}=0.58$

Compute the test statistic value as follows:

$z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.58-0.58}{\sqrt{\frac{0.58(1-0.58)}{400}}}=0$

The test statistic value is 0.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the p-value for the two-tailed test as follows:

$p-value=2\times P(z$

*Use a z-table for the probability.

The p-value of the test is 1.

The p-value of the test is very large when compared to the significance level.

The null hypothesis will not be rejected.

Thus, it can be concluded that the proportion of college students who work year-round is 58%.

6 0

3 years ago

Which graph below shows the rule:output 4 times input

Kipish [7]

Answer:bh5j67k

Step-by-step explanation:

5 0

3 years ago

Solve the attached question #yohaniJaman

aksik [14]

HETY is a parallelogram.

HT and EY are diagonals. We know that diagonals divides the parallelogram into two equal parts.

So ar(HET) = ar(HTY)

And, ar(HEY) = ar(EYT) now, in AHET, diagonal EY bisects the line segment HT and also the AHET,

∴ar(AHOE) = ar(AEOT)

Similarly in AETY

ar(ΔΕΟΤ) = ar(ΔΤΟΥ)

And in AHTY,

ar(ATOY) = ar(AHOY)

That means diagonals in parallelogram divides it into four equal parts.

Hence Proofed.

5 0

3 years ago

What is the distance from M(9,-4) to NC-1, -2)?

Ilia_Sergeevich [38]

Answer:

Exact Form: 2√26

Decimal Form: 10.19803902 …

Step-by-step explanation:

8 0

3 years ago