If de has endpoints D(-1,6)and E(3,-2),then the midpoint M of DE lies in Quadrant1

1 answer:

7 0

$M(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2}) \\M(\frac{-1 + 3}{2}, \frac{6 + (-2)}{2}) \\ M(\frac{2}{2}, \frac{6 - 2}{2}) \\ M(1, \frac{4}{2}) \\ M(1, 2)$

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a) 0.54 = 54% probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room or both.

b) 0.46 = 46% probability that a randomly selected person will not feel guilty for either of these reasons

Step-by-step explanation:

We use Venn's Equations for probabilities.

I am going to say that:

P(A) is the probability that a randomly selected person will feel guilty about wasting food.

P(B) is the probability that a randomly selected person will feel guilty about leaving lights on when not in a room.

0.12 probability that a randomly selected person will feel guilty for both of these reasons.

This means that $P(A \cap B) = 0.12$

0.27 probability that a randomly selected person will feel guilty about leaving lights on when not in a room.

This means that $P(B) = 0.27$

0.39 probability that a randomly selected person will feel guilty about wasting food

This means that $P(A) = 0.39$

a. What is the probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room or both (to 2 decimals)?

$P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.39 + 0.27 - 0.12 = 0.54$