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lianna [129]
3 years ago
6

Find the values of x and y (no links or report don’t answer if u don’t know )

Mathematics
1 answer:
AleksAgata [21]3 years ago
5 0
The x-axis is usually the horizontal axis, while the y-axis is the vertical axis. They are represented by two number lines that intersect perpendicularly at the origin, located at (0, 0), as shown in the figure below.
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Hey cam you guys please give me da answers
Nostrana [21]

10

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Help for both a and b
kipiarov [429]

Hi!

Remember that an x-intercept is a point in which the line touches the x-axis (the horizontal line). And, the y-intercept is a point in which the line touches the y-axis (the vertical/up and down line)

-----------------

For A)

The coordinate of the y-intercept is (0,1)

The coordinate of the x-intercept is (3,0)

For B)

The coordinate of the y-intercept is (0,0)

The coordinate of the x-intercept is (0,0) !

*both the x and y axis meet at the origin. So, a line that goes through the origin (0,0) is intersecting with BOTH the x and y-axis.

Hope I helped! Comment if you have any questions or concerns.

-Gabby5792

5 0
2 years ago
51 correct 9 incorrect as a fraction
BARSIC [14]
5 and 2/3 because 51/9= 5.666666667, which .66666667 in fraction form is 2/3
6 0
2 years ago
Solve for c.<br><br> a(c−b)=d
tatiyna

Answer:

c= ab + d/ a

Step-by-step explanation:

Let's solve for c.

a(c-b)=d

Step 1: Add ab to both sides.

-ab + ac + ab = d+ ab

ac = ab + d

Step 2: Divide both sides by a.

ac / a = ab + d / a

c = ab + d/ a

Answer:

c= ab + d/ a

Hope this helps ☝️☝☝

3 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
ddd [48]

Answer:

f'(x) = 4x^2 - 3 for x \le -3

Step-by-step explanation:

See attachment for proper question

Given

f(x) = -\frac{1}{2}\sqrt{x + 3}

For

x \ge -3

Required

Determine the inverse function

f(x) = -\frac{1}{2}\sqrt{x + 3}

Replace f(x) with y

y = -\frac{1}{2}\sqrt{x + 3}

Swap the positions of x and y

x = -\frac{1}{2}\sqrt{y + 3}

Multiply both sides by -2

-2 * x =-2 *  -\frac{1}{2}\sqrt{y + 3}

-2x =\sqrt{y + 3}

Square both sides

(-2x)^2 =(\sqrt{y + 3})^2

4x^2 =y + 3

Make y the subject

y = 4x^2 - 3

The inverse has been solved. So, we need to replace y with f'(x)

f'(x) = 4x^2 - 3

Next, is to determine the interval

x \ge -3

Change inequality to \le

x \le -3

Hence, the inverse function is:

f'(x) = 4x^2 - 3 for x \le -3

7 0
3 years ago
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