Answer:
The probability that none of the LED light bulbs are defective is 0.7374.
Step-by-step explanation:
The complete question is:
What is the probability that none of the LED light bulbs are defective?
Solution:
Let the random variable <em>X</em> represent the number of defective LED light bulbs.
The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.
A random sample of <em>n</em> = 10 LED light bulbs is selected.
The event of a specific LED light bulb being defective is independent of the other bulbs.
The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.
The probability mass function of <em>X</em> is:

Compute the probability that none of the LED light bulbs are defective as follows:


Thus, the probability that none of the LED light bulbs are defective is 0.7374.
Answer:
its C
Step-by-step explanation:
Subtract 2 from both sides
3x+2-2=5-2
3x=3
Divide both sides by 3
3x/3= 3/3
The answer is ×=1
Subtract 42 from 44.92 and then divide by 42. So it is 7%
Answer:
The cost of 80 oranges = 480 nairas
Step-by-step explanation:
Given
The cost of 5 oranges = 30 naira
Determine
The cost of 80 oranges
Given that the cost of 5 oranges = 30 naira
so,
Unit rate = 30 nairas / 5 oranges
= 6 nairas per orange
∴ The cost of 1 orange = 6 nairas
As the cost of 1 orange = 6 nairas
Thus,
The cost of 80 oranges = 6 × 80 = 480 nairas
Hence,
The cost of 80 oranges = 480 nairas