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3 years ago

If 120 L of an acid solution is 75% acid, how much pure acid is there in the mixture?

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

7 0

Answer:

25% or 30L

Step-by-step explanation:

100% is 120L, we know 75% is acid, we need the other 25% to make the 100%. 25% of 120 is 30, so 30 liters is pure acid

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Evaluate the expression when a = 2.<br> a^2+7a+7

Galina-37 [17]

Answer:

Step-by-step explanation:

a² + 7a + 7

a = 2

Plug in the value of 2 for every occurance of a.

(2)² + 7(2) + 7

First, solve the exponent.

4 + 7(2) + 7

Now, multiply.

4 + 14 + 7.

Add.

This is your answer.

Hope this helps!

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3 years ago

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3 years ago

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3 years ago

The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:

deff fn [24]

Step-by-step explanation:

Given equation of circle is,

${x}^{2} + {y}^{2} - 6y - 12 = 0 \\ by \: compairing \: it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f= - 6 \\ or \: f= - 3 \\ c = - 12$

again the another form of circle is,

${x}^{2} + {(y - k)}^{2} = 21 \\ or \: {x}^{2} + {y}^{2} - 2ky + {k}^{2} - 21 = 0 \\ by \: compairing \:it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\ g = 0 \\f = - k \\ c = {k}^{2} - 21$

now equating the values of f in both equations,

-k=-3

i.e. k=3

therefore k=3

4 0

3 years ago