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2 years ago

Choose the correct slant asymptote for the function, y=x^2-5x-6/x-6

Mathematics

1 answer:

pishuonlain [190]2 years ago

4 0

Answer:

y = x + 1

Step-by-step explanation:

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Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypot

Nina [5.8K]

Answer: a. 0.1031; fail to reject the null hypothesis

Step-by-step explanation:

Given: Significance level : $\alpha=0.05$

The test statistic in a two-tailed test is z = -1.63.

The P-value for two-tailed test : $2P(Z>|z|)=2P(Z>|-1.63|)=0.1031$ [By p-value table]

Since, 0.1031 > 0.05

i.e. p-value > $\alpha$

So, we fail to reject the null hypothesis. [When p< $\alpha$ then we reject null hypothesis ]

So, the correct option is a. 0.1031; fail to reject the null hypothesis.

8 0

2 years ago

The director of admissions at Kinzua University in Nova Scotia estimated the distribution of student admissions for the fall sem

wariber [46]

Answer:

In order to calculate the expected value we can use the following formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And if we use the values obtained we got:

$E(X)=(1060*0.5) +(1400*0.1) +(1620*0.4)=1318$

Step-by-step explanation:

Let X the random variable that represent the number of admisions at the universit, and we have this probability distribution given:

X 1060 1400 1620

P(X) 0.5 0.1 0.4

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).

And the standard deviation of a random variable X is just the square root of the variance.

In order to calculate the expected value we can use the following formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And if we use the values obtained we got:

$E(X)=(1060*0.5) +(1400*0.1) +(1620*0.4)=1318$

3 0

2 years ago

Which is greater? <br> 0.7=7/10 or 7/9

amm1812

The correct answer is 7/9

6 0

3 years ago

Ali surveyed 200 students at a school and recorded the eye color and the gender of each student. of the 80 male students who wer

Aloiza [94]

Total number of students surveyed = 200
Number of male students = 80
Number of female students = 200 - 80 = 120

Number of brown eyed male students = 60
Probability of a brown eyed male student = 60 / 80 = 0.75.

Since, <span>eye color and gender are independent, this means that eye color is not affected by the gender. Thus, we expect a similar probability of brown eye for female as we had for male.

Let the number expected of brown eyed females be x, then x / 120 = 0.75.

Thus, x = 120(0.75) = 90.

Therefore, the number female students surveyed expected to be brown eyed is 90.</span>

7 0

3 years ago

40 point question !!!<br> If you zoom in on the pic it doesn’t have the strobe like effect !

wlad13 [49]

Answer:

Step-by-step explanation:

4 0

2 years ago