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vlabodo [156]
2 years ago
6

A motorbike travels 165 km in 3 hours. How long will it take to travel 440 km?

Mathematics
2 answers:
hichkok12 [17]2 years ago
6 0
It will take 8 hrs I think sorry if I’m wrong
Andre45 [30]2 years ago
4 0

Answer:

165km ----> 3 hrs

1km --------> (3/165) hrs

440km -------->  [(3/165)*440]hr

Answer: 8 hrs

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Drew has 50 red, green, and blue marbles. He has six more red marbles than blue marbles and four fewer green marbles than blue m
Yanka [14]
Drew has 56 Red Marbles, 56 Green Marbles, Drew has about 60 Blue Marbles. First i added 6 to Red since Red Has 6 More Marbles Than Blue, Then i added Subtracted 4 from green, which resulted in 46 Green Marbles. Finally i added 4 and 6 to get 60 Blue Marbles. I am not sure if i am correct, but i gave it a shot! ^-^
4 0
3 years ago
In January, Wally's Widget World had sales of $12,500 and expenses of $10,200. The profit for January was _____.
likoan [24]
Easy, $12, 500 - $10, 200 = ?
8 0
3 years ago
Simplify. Assume that all variables are positive.
mihalych1998 [28]

Answer: -3x^{2} y\sqrt[3]{2y}

Step-by-step explanation:

7 0
2 years ago
Help me with this please
meriva

Answer:

1) E

2) D

3) G

4) I

Step-by-step explanation:

1)

P = 2(l + w)

P = 2(3a + 3 + 8a - 12)

P = 2(11a - 9)

P = 22a - 18

2)

P = 22a - 18

P = 22(3) - 18

P = 66 - 18

P = 48

3)

P = a + b + c

P = 3b + 7 + 7b - 2 + 7b - 2

P = 17b + 3

4)

P = 17b + 3

P = 17(6) + 3

P = 102 + 3

P = 105

6 0
2 years ago
P³ = 1/8 please help me if anybody can .
ivanzaharov [21]

Answer:

p= \dfrac{1}{2}

Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}

\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}

\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

\implies p= \dfrac{1}{8^{\frac{1}{3}}}

Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}

Simplify:

\implies p= \dfrac{1}{2^{\frac{3}{3}}}

\implies p= \dfrac{1}{2^{1}}

\implies p= \dfrac{1}{2}

3 0
1 year ago
Read 2 more answers
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