Lucy had $72, which is nine times as much money as Xavier had. How much money did Xavier have? Select the correct solution metho
2 answers:
Answer:
9x = 72. Divide both sides by 9. Xavier had $8.
Step-by-step explanation:
LEt x be the amount of money Xavier have.
Lucy had $72, which is nine times as much money as Xavier had
Lucy had 9 times the Xavier had
Lucy had 9 times the x
So the equation becomes
Divide both sides by 9 to solve for x
So Xavier had $8
9x = 72. Divide both sides by 9. Xavier had $8.
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Answer:
a)
b) Since the sample size is large enough n>30 and the original distribution for the random variable X doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.
c)
d) See figure attached
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Let X the random variable of interest. We know from the problem that the distribution for the random variable X is given by:
We take a sample of n=40 . That represent the sample size
Part a
From the central limit theorem we know that the distribution for the sample mean is also normal and is given by:
Part b
Since the sample size is large enough n>30 and the original distribution for the random variable X doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.
Part c
In order to answer this question we can use the z score in order to find the probabilities, the formula given by:
And we want to find this probability:
We can us the following excel code: "=NORM.DIST(1.807,0,1,TRUE)"
Part d
See the figure attached.
