Question

Lucy had $72, which is nine times as much money as Xavier had. How much money did Xavier have? Select the correct solution method below, representing Xavier's money with x.
a. Multiply both sides by 9. Xavier had $648.
b.x – 9 = 72. Add 9 to both sides. Xavier had $81.
c.x + 9 = 72. Subtract 9 from both sides. Xavier had $63.
d.9x = 72. Divide both sides by 9. Xavier had $8.

Answer 1

D is the correct answer.

Answer 2

Answer:

9x = 72. Divide both sides by 9. Xavier had $8.

Step-by-step explanation:

LEt x be the amount of money Xavier have.

Lucy had $72, which is nine times as much money as Xavier had

Lucy had 9 times the Xavier had

Lucy had 9 times the x

So the equation becomes $72= 9x$

$9x=72$

Divide both sides by 9 to solve for x

$x=8$

So Xavier had $8

9x = 72. Divide both sides by 9. Xavier had $8.