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Elena-2011 [213]
3 years ago
12

Students are selling hand-made magnets at the school craft fair. One magnet costs $0.30, 2 magnets cost $0.43, 3 magnets cost $0

.56, and 4 magnets cost $0.69. If this pattern continues, how much will 6 magnets cost? Explain how you found your answer
Mathematics
1 answer:
Sliva [168]3 years ago
6 0
1 = 0.30 
2 = 0.43
3 = 0.56
4 = 0.69 
5 = 0.82
6=  0.95 

To find by how much you are adding every time , you have to subtract the 2 magnet cost (0.43) from the 1 magnet cost (0.30) and this equals 0.13
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A conference planner has put together 280 binders for attendees and another 31 binders for presenters.how many total binders did
Ede4ka [16]

Answer:

311

Step-by-step explanation:

280 + 31 = 311

3 0
3 years ago
A^3+a+a^2+1 2a^2+2ab+ab^2+b^3
Vikentia [17]
\frac{a^3+a+a^2+1}{a^3+a^2+ab^2+b^2} \cdot  \frac{2a^2+2ab+ab^2+b^3}{a^3+a+a^2b+b} =\frac{a(a^2+1)+1(a^2+1)}{a^2(a+1)+b^2(a+1)} \cdot  \frac{2a(a+b)+b^2(a+b)}{a(a^2+1)+b(a^2+1)} =\\\\=\frac{(a^2+1)(a+1)}{(a+1)(a^2+b^2)} \cdot  \frac{(a+b)(2a+b^2)}{(a^2+1)(a+b)} = \frac{2a+b^2}{a^2+b^2}
6 0
3 years ago
The first five terms of a linear sequence are given below. 7 , 12 , 17, 22 , 27 , ... What is the next term of the sequence?
Norma-Jean [14]

Answer:

<h2>32</h2>

Step-by-step explanation:

a_1=7\\a_2=7+5=12\\a_3=12+5=17\\a_4=17+5=22\\a_5=22+5=27\\\\a_6=27+5=32\\a_7=32+5=37\\a_8=37+5=42\\a_9=42+5=47\\\vdots

8 0
3 years ago
Sherman has two sequences . The first sequence is described by the explicit rule f(n) = 15n + 4 and the second sequence is descr
Viktor [21]

Answer:

Step-by-step explanation:

Given the explicit function as

f(n) = 15n+4

The first term of the sequence is at when n= 1

f(1) = 15(1)+4

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 15(2)+4

f(2) = 34

d = 34-19

d = 15

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)15)

S20 = 10(38+19(15))

S20 = 10(38+285)

S20 = 10(323)

S20 = 3230.

Sum of the 20th term is 3230

For the explicit function

f(n) = 4n+15

f(1) = 4(1)+15

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 4(2)+15

f(2) = 23

d = 23-19

d = 4

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)4)

S20 = 10(38+19(4))

S20 = 10(38+76)

S20 = 10(114)

S20 = 1140

Sum of the 20th terms is 1140

7 0
2 years ago
X = 10<br><br> x = 2<br><br> x = two divided by five.<br><br> x = 11
KengaRu [80]

Answer:

x = 10

Step-by-step explanation:

You can try the answers to see which works. (The first one does.)

Or, you can solve for the variable:

Divide by 75

... (1/5)^(x/5) = 3/75 = 1/25

Recognize that 25 = 5^2, so ...

... (1/5)^(x/5) = (1/5)^2

Equating exponents, you have

... x/5 = 2

... x = 10 . . . . . multiply by 5

_____

You can also start by taking logarithms:

... log(75) +(x/5)log(1/5) = log(3)

... (x/5)log(1/5) = log(3) -log(75) = log(3/75) = log(1/25) . . . . simplify the log

... x/5 = log(1/25)/log(1/5) = 2 . . . . . simplify (or evaluate) the log expression

... x = 10 . . . . . multiply by 5

_____

"Equating exponents" is essentially the same as taking logarithms.

5 0
3 years ago
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