Question

...what are consecutive multiples ​

Answer 1

Answer:

H

Step-by-step explanation:

Let represent A and B

A and B is the sum of the first 50 consecutive multiples of 3 and 6, this is the same as a arithmetic sequence because arithmetic sequences have a common sum.

We can represent this as

$a _{n} = a {}^{1} + d(n - 1)$

where a^1 is the first term, d is the common sum, n is the number of multiples we adding.

The first term for both A and B respectively is 3 and 6.

Multiples implies that the Difference between A and B are 3 and 6 respectively. There are 50 consecutively. multiples.

Plug in the known parts for both.

$3 + 3(49) = 150$

$6 + 6(49) = 300$

We need to what percent of find 150% of 300.

B is twice as A, so this means that we need to multiply 2 by it original or 100% of it self.

$2 \times 100 = 200$

So 200% is the answer.