All categories

2 years ago

Which of the following points lies on the graph of y = 3x-5

Mathematics

1 answer:

andreyandreev [35.5K]2 years ago

6 0

Answer:

(4,7)

Step-by-step explanation:

I have attached what the graph looks like below.

Looking at it, you will see the point (4,7) lies on the graph.

So the answer is 2)

You might be interested in

-2(7a+4b)-6c=<br> Simplify

jeka94

Answer:

Because of the minus sign

2 becomes - 2

The answer is -2

Multiply a and 7

Multiply a and 1

The a just gets copied along.

The answer is a

7*a evaluates to 7a

Multiply b and 4

Multiply b and 1

The b just gets copied along.

The answer is b

4*b evaluates to 4b

7*a+4*b evaluates to 7a+4b

Multiply -2 by 7a+4b

we multiply -2 by each term in 7a+4b term by term.

This is the distributive property of multiplication.

Multiply -2 and 7a

Multiply 1 and a

The a just gets copied along.

-2 × 7a = -14a

Multiply -2 and 4b

Multiply 1 and b

The b just gets copied along.

-2 × 4b = -8b

-2*(7*a+4*b) evaluates to -14a-8b

Multiply c and 6

Multiply c and 1

The c just gets copied along.

The answer is c

6*c evaluates to 6c

The answer is -14a-8b-6c

-2*(7*a+4*b)-6*c evaluates to -14a-8b-6c

The final answer is

-14a-8b-6c

Step-by-step explanation:

Please mark brainliest and have a great day!

4 0

3 years ago

When the factors of a trinomial are (x - p) and (x - q) then the constant term of the trinomial is:

padilas [110]

Its the product of -p and -q

that is b.

4 0

3 years ago

Read 2 more answers

Sandra bought 4 pounds of sweet potatoes for $5.40. What is the cost per pound of the sweet potatoes?

zvonat [6]

Answer:

$1.35

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Can someone please answer this?

galina1969 [7]

Since we know the side length of the square (6), we can calculate its diagonal using pythagoras.

diag d = √(6²+6²) = 6√2 in

The diagonal is also the diameter of the circle! So the radius of the circle is half of that:

radius r = d/2 = 3√2 in

The area of the circle is πr² = π(3√2)² = 18π in²

5 0

3 years ago

Which of the following sets are subspaces of R3 ?

Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

$\to A={(x,y,z)|3x+8y-5z=2} \\\\\to for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)$

The set A is not part of the subspace $R^3$

for point B:

$\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0$

$\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon B$

The set B is part of the subspace $R^3$

for point C: $\to C={(x,y,z)|x$

In this, the scalar multiplication can't behold

$\to for (-2,-1,2) \varepsilon C$

$\to -1(-2,-1,2)= (2,1,-1)$ ∉ C

this inequality is not hold

The set C is not a part of the subspace $R^3$

for point D:

$\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)$

The scalar multiplication s is not to hold

$\to for (-4, 1,2)\varepsilon D\\\\\to -1(-4,1,2) = (4,-1,-2)$ ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace $R^3$

For point E:

$\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\$

The $x_1, x_2$ is the arbitrary, in which $ax_1+bx_2$ is arbitrary

$\to a(x_1,0,0)+b(x_2,0,0) \varepsilon E$

The set E is the part of the subspace $R^3$

For point F:

$\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon F \\\\\to a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))$

The $x_1, x_2$ arbitrary so, they have $ax_1+bx_2$ as the arbitrary $\to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F$

The set F is the subspace of $R^3$

5 0

3 years ago