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kow [346]
3 years ago
10

Please help me figure out this math problem

Mathematics
1 answer:
Elis [28]3 years ago
6 0
It will have to be c because of the ay it moved
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Triangle FGH is an equilateral triangle.FH=6x+1,FG=3x+10,and GH=9x-8
Lena [83]

Answer:

Acute triangle

x = 3

GH = 19

Step-by-step explanation:

7 0
3 years ago
Find f(-2) for f(x) = 3.2.<br> O A. 2/1<br> OB.<br> 36<br> O C. -36<br> OD. -12<br> 3/4
valina [46]

Answer:

3/4 (A)

Step-by-step explanation:

replace x with -2 in the function

3 · 2^-2  = 3 · 0.25

3 · 0.25 = 0.75

0.75 = 3/4

3 0
2 years ago
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What is the solution to the inequality 14y−14≥14?
makkiz [27]
14y > 0 is the answer
6 0
3 years ago
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A city has 3 new houses for every 9 old houses. If there are 15 new houses in the city, how many old houses are there?
Arisa [49]

Answer:

45 old houses

Step-by-step explanation:

new houses : old houses

3 : 9

15 : ?

(3 = 1st ratio and 9 = 2nd ratio)

To find the missing ratio, divide the first ratio from the new ratio:

15 / 3 = 5

Take the product and multiply that by the second ratio to find the missing ratio:

9 x 5 = 45

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3 years ago
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Find the exact value of the trigonometric expression given that sin u = − 8 17 and cos v = − 24 25 . (Both u and v are in Quadra
Rashid [163]

Answer: sin u = -5/13 and cos v = -15/17

Step-by-step explanation:

The nice thing about trig, a little information goes a long way. That’s because there is a lot of geometry and structure in the subject. If I have sin u = opp/hyp, then I know opp is the opposite side from u, and the hypotenuse is hyp, and the adjacent side must fit the Pythagorean equation opp^2 + adj^2 = hyp^2.

So for u: (-5)^2 + adj^2 = 13^2, so with what you gave us (Quad 3),

==> adj of u = -12 therefore cos u = -12/13

Same argument for v: adj = -15,

opp^2 + (-15)^2 = 17^2 ==> opp = -8 therefore sin v = -8/17

The cosine rule for cos (u + v) = (cos u)(cos v) - (sin u)(sin v) and now we substitute: cos (u + v) = (-12/13)(-15/17) - (-5/13)(-8/17)

I am too lazy to do the remaining arithmetic, but I think we have created a way to approach all of the similar problems.

3 0
3 years ago
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