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3 years ago

(fg)-1(5)=g-1f-1(5)

Mathematics

1 answer:

larisa86 [58]3 years ago

6 0

Answer:

f = g/ g+1

Step-by-step explanation:

Remove Parenthesis.

fg - 1 x 5 = g - 1 x f - 1 x 5

Cancel -1 x 5 on both sides.

fg = g - 1 x f

Simplify 1 x f to f.

fg = g - f

Add f to both sides.

fg + f = g

Factor out the common term f.

f (g + 1) = g

Divide both sides by g + 1

f = g/ g + 1

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2 years ago

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$\large\boxed{\text{No.}\ \dfrac{0.5}{1}\neq\dfrac{1}{1.5}\neq\dfrac{1.5}{2}}$

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$\text{Let}\\ a,\ b,\ c\ -\ \text{sides of a triangle ABC, where}\ a\leq b\leq c\\d,\ e,\ f\ -\ \text{sides of a triangle}\ DE F,\ \text{where}\ d\leq e\leq f.\\\\\triangle ABC\sim\triangle DE F\iff\dfrac{a}{d}=\dfrac{b}{e}=\dfrac{c}{f}\\\\/\text{corresponding sides are in proportion}/$

$\bold{WARNING !!!}\\\\\text{No triangle like QRS exists!}\\\\1 + 0.5 = 1.5 !!!\\\\\text{The sum of the lengths of the two shorter sides of the triangle}\\\text{must be greater than the length of the longest side.}$

$\text{Despite this, let's check the ratios}$

$\text{We have:}\\\\\triangle XYZ\to a=1,\ b=1.5,\ c=2\\\triangle QRS\to d=0.5,\ e=1,\ f=1.5$

$\text{Check:}\\\\\dfrac{d}{a}=\dfrac{0.5}{1}=0.5\\\\\dfrac{e}{b}=\dfrac{1}{1.5}=\dfrac{10}{15}=\dfrac{2}{3}\\\\\dfrac{f}{c}=\dfrac{1.5}{2}=\dfrac{15}{20}=\dfrac{3}{4}\\\\\dfrac{d}{a}\neq\dfrac{e}{b}\neq\dfrac{f}{c}\neq\dfrac{d}{a}$

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2 years ago

(fg)-1(5)=g-1f-1(5)​

(fg)-1(5)=g-1f-1(5)