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Kitty [74]
3 years ago
12

I have no idea what i’m doing

Mathematics
1 answer:
cestrela7 [59]3 years ago
7 0

Answer:

f(x)=x^2+1 -> f(a+1)=(a+1)^2+1=a^2+2a+1+1=a^2+2a+2

Step-by-step explanation:

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1. Candace has $15 more than Amar. Their combined money totals $85. Which system of equations represents this situation? F. c +
ollegr [7]
The answer would be C+A= $85 or A+C=$85

Explanation: Candaces total money + Amar’s total money equals out to $85, it can be wrote either way and still equal $85.
4 0
3 years ago
Triangle ABC had a perimeter 18 cm
Alex

Step-by-step explanation:

what is the main condition the lengths of the sides of a right-angled triangle have to fulfill ?

Pythagoras !

c² = a² + b²

c is the Hypotenuse (the baseline opposite of the 90 degree angle), a and b are the so-called legs (the sides enclosing the 90 degree angle).

only if there is a combination of the sides, for which the Pythagoras equation is true, do we have a right-angled triangle. otherwise not.

we also know CA = 18 - 7 - 3 = 8 cm

so, let's try

8² = 7² + 3²

64 = 49 + 9 = 58 wrong

7² = 8² + 3²

49 = 64 + 9 = 73 wrong

3² = 8² + 7²

9 = 64 + 49 = 113 wrong

so, there is no combination, where the Pythagoras equation is true, so it is NOT a right-angled triangle.

4 0
3 years ago
Please help me with this question, image attached.
goldfiish [28.3K]
You need to 8 + 4 = 12 and take the half of 12 and start at -4 and count up 6
8 0
3 years ago
Math test! i need help!
Maslowich

Answer:

<em>t</em> ≤ -3

Step-by-step explanation:

divide both sides by 5

8 0
3 years ago
Read 2 more answers
A group of 121 Internet users 50-65 years of age were randomly chosen and asked to report the weekly number of hours they spend
Luda [366]

Answer: We support the null hypothesis.

Step-by-step explanation:

Given : The purpose of the study was to determine whether the mean weekly number of hours that Internet users in that age group spend online differs from the mean for Internet users in general which is 12.50 hours.

The set of hypothesis for the given claim :-

H_0:\mu=12.50\\\\ H_a:\mu\neq12.50

A 95% confidence interval for the mean weekly number of hours that Internet users in that age group spend online was calculated to be (11.439 , 12.577).

Since 12.50 contained in the 95% confidence interval (11.439 , 12.577).

Therefore, we support the null hypothesis.

So the final conclusion will be, we have evidence to support the claim that Internet users in that age group spend online differs from the mean for Internet users in general which is 12.50 hours.

7 0
4 years ago
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