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3 years ago

Through (4,3), perpendicular to 2x-5y=7

1 answer:

8 0

First you want to get it to y=mx+b. to do this you have to get the y by itself on one side. 2x-5y=7 you bring -5y over and get 2x=5y+7. Then bring the 7 over and get 2x-7=5y and finally get rid of the 5 by dividing both sides by it 2x-7/5 turns into 2/5x-7/5 and 5y becomes y. Y=2/5X-7/5. Next to get the slope of a line perpendicular to another you first flip the original slope (2/5x to 5/2x) and then reverse the sign (5/2x to -5/2x). and now you have Y=-5/2X+B. To get B you must put in what you know (X is 4, Y is 3) Get 3=-5/2(4)+B and solve.
3=-5/2(4)+B to 3=-10+B. bring -10 over and get 13=B and put that in. Finally you have Y=-5/2X+13.

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Solve the equation for the unknown variable.

olga nikolaevna [1]

Answer:

b x 3 = 8

=> b = 8/3

Hope this helps!

4 0

3 years ago

2x2-y if x=3 and y=8

9966 [12]

The answer is 0 because when you plug in the 3 and the 8 into the equation and do order of operations you will get 0.

8 0

3 years ago

I need this answered its due soon

mixer [17]

A is false because this graph doesn't have any relative minimums because it never increases

B is false because this graph never increases

C is true

D is true because the graph never goes below 3, but it's blurry so I might be wrong

E is true because it never stops decreasing and has a domain of all real numbers

7 0

2 years ago

A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0

3 years ago

An investor plans to invest $500 a year and expects to get a 10.5% return. If the investor makes these contributions at the end

taurus [48]

The present value of the investment is $6000.

According to the statement

Principal amount = $500

and Return amount = 10.5%

Time period = 20 years.

Now we find the present value of money then

By the formula

PV = P[1-(1+r)^n]/r

PV = 500[1-(1+0.10)^20]/0.10

PV = 6000

So, The present value of the investment is $6000.

Learn more about Return Amount here brainly.com/question/2456547

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4 0

1 year ago