Through (4,3), perpendicular to 2x-5y=7

1 answer:

8 0

First you want to get it to y=mx+b. to do this you have to get the y by itself on one side. 2x-5y=7 you bring -5y over and get 2x=5y+7. Then bring the 7 over and get 2x-7=5y and finally get rid of the 5 by dividing both sides by it 2x-7/5 turns into 2/5x-7/5 and 5y becomes y. Y=2/5X-7/5. Next to get the slope of a line perpendicular to another you first flip the original slope (2/5x to 5/2x) and then reverse the sign (5/2x to -5/2x). and now you have Y=-5/2X+B. To get B you must put in what you know (X is 4, Y is 3) Get 3=-5/2(4)+B and solve.
3=-5/2(4)+B to 3=-10+B. bring -10 over and get 13=B and put that in. Finally you have Y=-5/2X+13.

You might be interested in

A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple. how many ways are there to choose:

swat32

Is this a probability question?

7 0

3 years ago

Find the value of x to the nearest tenth

kenny6666 [7]

Step-by-step explanation:

I think this might help

5 0

3 years ago

(2-5i)(4+7i)? How do u do this? HELPPPPPPPP

krek1111 [17]

The "I"'s r variables, now u do 2-5 which sequels -2. now u do 4+7 and that ='s 11. now I think u take 11 and -2 and u subtract 11-(-2). or it could be change the negative into a positive and add them together.

3 0

3 years ago

State a cubic or quartic function with the least degree possible in intercept form for the given graph. Assume that all x-interc

Iteru [2.4K]

Answer:

y = $-x^{3} - 2x^{2} + 5x + 6$