Question

How do i put this in slope-intercept form. passes through 2,-2 and 4,-1​

Answer 1

Answer:

$\large\boxed{y=\dfrac{1}{2}x-3}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have two points (2, -2) and (4, -1).

Substitute:

$m=\dfrac{-1-(-2)}{4-2}=\dfrac{-1+2}{2}=\dfrac{1}{2}$

Put the value of a slope and the coordinates of the point (2, -2) to the equation of a line:

$-2=\dfrac{1}{2}(2)+b$

$-2=1+b$              subtract 1 from both sides

$-3=b\to b=-3$

Finally:

$y=\dfrac{1}{2}x-3$