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vodka [1.7K]
3 years ago
8

What is the answer to the math problem?

Mathematics
1 answer:
Sergio039 [100]3 years ago
6 0
Sorry I can't see most of the question so I can't answer it!
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Jonathan purchases 15 pounds of bananas for $.49 a pound. How much did Jonathan pay
ExtremeBDS [4]

Answer:

$7.35

Step-by-step explanation:

To find the answer to this question, you would need to multiply 15 times .49 which would equal 7.35

5 0
3 years ago
What is 2x6x4 im in elementary by the way
dolphi86 [110]

Answer:

48

Step-by-step explanation:

2x6=12

12x4= 48

8 0
2 years ago
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Use the graph of the function to find, f(-2).<br><br> A. -2<br> B. -1<br> C. 1<br> D. 2
Misha Larkins [42]

Since f(-2) means that our x-value is -2, we can go to that position on the graph and slide up the y-axis to find the intersection this point has with the function graphed.

If I am correct the answer should be that the y value is 2!

7 0
3 years ago
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The The Laplace Transform of a function , which is defined for all , is denoted by and is defined by the improper integral , as
guapka [62]

Answer:

a. L{t} = 1/s² b. L{1} = 1/s

Step-by-step explanation:

Here is the complete question

The The Laplace Transform of a function ft), which is defined for all t2 0, is denoted by Lf(t)) and is defined by the improper integral Lf))s)J" e-st . f(C)dt, as long as it converges. Laplace Transform is very useful in physics and engineering for solving certain linear ordinary differential equations. (Hint: think of s as a fixed constant) 1. Find Lft) (hint: remember integration by parts) A. None of these. B. O C. D. 1 E. F. -s2 2. Find L(1) A. 1 B. None of these. C. 1 D.-s E. 0

Solution

a. L{t}

L{t} = ∫₀⁰⁰e^{-st}t

Integrating by parts  ∫udv/dt = uv - ∫vdu/dt where u = t and dv/dt = e^{-st} and v = \frac{e^{-st}}{-s} and du/dt = dt/dt = 1

So, ∫₀⁰⁰udv/dt = uv - ∫₀⁰⁰vdu/dt w

So,  ∫₀⁰⁰e^{-st}t =  [\frac{te^{-st}}{-s}]₀⁰⁰ -  ∫₀⁰⁰ \frac{e^{-st}}{-s}

∫₀⁰⁰e^{-st}t =  [\frac{te^{-st}}{-s}]₀⁰⁰ -  ∫₀⁰⁰ \frac{e^{-st}}{-s}

= -1/s(∞exp(-∞s) - 0 × exp(-0s)) + \frac{1}{s} [\frac{e^{-st} }{-s}]₀⁰⁰

= -1/s[(∞exp(-∞) - 0 × exp(0)] - 1/s²[exp(-∞s) - exp(-0s)]

= -1/s[(∞ × 0 - 0 × 1] - 1/s²[exp(-∞) - exp(-0)]

= -1/s[(0 - 0] - 1/s²[0 - 1]

= -1/s[(0] - 1/s²[- 1]

= 0 + 1/s²

= 1/s²

L{t} = 1/s²

b. L{1}

L{1} = ∫₀⁰⁰e^{-st}1

= [\frac{e^{-st} }{-s}]₀⁰⁰

= -1/s[exp(-∞s) - exp(-0s)]

= -1/s[exp(-∞) - exp(-0)]

= -1/s[0 - 1]

= -1/s(-1)

= 1/s

L{1} = 1/s

6 0
3 years ago
The price of Air jordans markdown from $110-$70 by what percentage was the price reduced
anyanavicka [17]
If the Air Jordans were originally $110 and are now $70 then the percentage off is 36.3636%
3 0
3 years ago
Read 2 more answers
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