Answer:
1.7 miles
Step-by-step explanation:
Given that,
Jacob walks 1.5 miles north.
He turns and walks 0.8 miles west.
We need to find how far is he from his starting point. Let he is at a distance of x miles from the starting point. It can be calculated as follows :
Hence, he is 1.7 miles from his starting point.
<u><em>Answer:</em></u>
Her hourly rate is $8.25
<u><em>Explanation:</em></u>
Tatianna works 3 hours a day on school days and makes a total of $123.75 in a week
<u>We know that:</u>
There are 5 school days in a week
<u>We are given that:</u>
She works for 3 hours a day each of those days
<u>Therefore:</u>
Total number of hours worked = hours worked daily * number of days
Total number of hours worked = 3 * 5 = 15 hours in a week
<u>The equation used to calculate Tatianna's earnings is:</u>
Amount she makes in a week = Total number of hours worked * hourly rate
<u>Now, we substitute with the givens to get the hourly rate as follows:</u>
Amount she makes in a week = Total number of hours worked * hourly rate
123.75 = 15 * hourly rate
Hourly rate = $8.25
Answer:
58 units squared
Step-by-step explanation:
We want to find the area of the square. To do so, we need to find the hypotenuse of the right triangle because this coincides with the side length of the square.
We use the Pythagorean Theorem, which states that for a right triangle with legs a and b and hypotenuse c:
a^2 + b^2 = c^2
Here, a = 7 and b = 3, so:
7^2 + 3^2 = c^2
c^2 = 49 + 9 = 58
Now, the area of a square is: A = s^2, where s is the side length. Well, c is the side length, and we've already found what c^2 is (it's 58), so that means the area of the square is 58 units squared.
Thus, the answer is 58 units squared.
The arc length of the semicircle is 5π units
<h3>Calculating length of an arc</h3>
From the question, we are to calculate the arc length of the semicircle
Arc length of a semicircle = 1/2 the circumference of the circle
∴ Arc length of a semicircle = 1/2 × 2πr
Arc length of a semicircle = πr
Where r is the radius
From the given information,
r = 5
∴ Arc length of the semicircle = 5 × π
Arc length of the semicircle = 5π units
Hence, the arc length of the semicircle is 5π units
Learn more on Calculating length of an arc here: brainly.com/question/16552139
#SPJ1
Answer:24 cm
Step-by-step explanation:
every 14 hours 2.8 cm gets worn down so
divide it and you get .2cm/hr so will be 24 cm
