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fgiga [73]
3 years ago
15

Please someone help me on how to do grids?

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
6 0
It’s actually 15. It’s in between 10 and 20
mafiozo [28]3 years ago
4 0
Answer:

25

Step-by-step explanation:

Question: The distance between P and T on the coordinate grid is __ units. (Input whole numbers only.)

Answer + Step-by-step explanation:

Step 1. Find where point P is located at

Answer: (-10, 15)

Step 2. Find where point T is located at

Answer: (15, 15)

Step 3. Find the distance between point P and T.

Answer: (25) Steps in image

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Find the slope of the line that passes through (6 , 2) and ( 1 ,10).
DochEvi [55]

Answer: Slope: -1.6

Use the slope formula

substitute point values in the formula

                              (10 -2)

- like this:       m = ----------

                              (1 - 6)

Simplify each other side of the equation

- simplified: 8/-5

m: - 1.6

7 0
3 years ago
Find the measure of angle indicated
Rus_ich [418]

Answer:

there is no question

Step-by-step explanation:

there is no question/angle so i don't know how to help you

7 0
3 years ago
The position function of a particle in rectilinear motion is given by s(t) = 2t^3 + 21t^2 + 60t + 3 for t ≥ 0 with t measured in
natta225 [31]
As the fellow above said, the particle does make a U-turn at the vertex, and we can find that out by getting the derivative of s(t) and zeroing it out to get the point of the horizontal tangent.

Bearing in mind that ds/dt is really v(t) or the velocity equation, so when we zero out the ds/dt, is the same as saying the velocity went to 0, since it got zeroed out, and then the particle goes over the vertex and changes direction.

\bf s(t)=2t^3-21t^2+60t+3\implies \boxed{\cfrac{ds}{dt}=6t^2-42t+60}\leftarrow v(t)
\\\\\\
0=6t^2-42t+60\implies 0=t^2-7t+10\implies 0=(t-5)(t-2)
\\\\\\
t=
\begin{cases}
5\\
2
\end{cases}\impliedby \textit{it makes the first turn at the \underline{2 second}}
\\\\\\
\textit{now let's find the acceleration equation, a(t)}
\\\\\\
\boxed{\cfrac{d^2s}{dt^2}=12t-42}\leftarrow a(t)\\\\
-------------------------------\\\\
s(2)=55\qquad \qquad \qquad \qquad a(2)=-18

the negative acceleration value, simply means a decreasing rate of change, so, it means the particle is slowing down and possibly coming to a stop before changing direction again.
8 0
3 years ago
Hey can you please help me posted picture of question
AlekseyPX
We have the following function:
 N (k):
 Where, the indepent variable is k
 The dependent variable is N
 For the function:
 k (n):
 the independent variable is n
 The dependent variable is k
 Thus,
 N (12) = 4
 k (4) = 12
 Answer:
 
TRUE
 
option A
8 0
3 years ago
What is the surface area of the square pyramid represented by the net?
ANTONII [103]
Heck yeah!!!
ok so do 5x3=15 divide by 2(really don't need to do that!)
15x 2=30 or 7.5x4=30
then add 3x3=9 to 30 so 9+30=39
ur answer is 39

hope this helps!!!!
6 0
3 years ago
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