Please someone help me on how to do grids?
2 answers:
Answer:
25
Step-by-step explanation:
Question: The distance between P and T on the coordinate grid is __ units. (Input whole numbers only.)
Answer + Step-by-step explanation:
Step 1. Find where point P is located at
Answer: (-10, 15)
Step 2. Find where point T is located at
Answer: (15, 15)
Step 3. Find the distance between point P and T.
Answer: (25) Steps in image
25
Step-by-step explanation:
Question: The distance between P and T on the coordinate grid is __ units. (Input whole numbers only.)
Answer + Step-by-step explanation:
Step 1. Find where point P is located at
Answer: (-10, 15)
Step 2. Find where point T is located at
Answer: (15, 15)
Step 3. Find the distance between point P and T.
Answer: (25) Steps in image
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As the fellow above said, the particle does make a U-turn at the vertex, and we can find that out by getting the derivative of s(t) and zeroing it out to get the point of the horizontal tangent.
Bearing in mind that ds/dt is really v(t) or the velocity equation, so when we zero out the ds/dt, is the same as saying the velocity went to 0, since it got zeroed out, and then the particle goes over the vertex and changes direction.
the negative acceleration value, simply means a decreasing rate of change, so, it means the particle is slowing down and possibly coming to a stop before changing direction again.
Bearing in mind that ds/dt is really v(t) or the velocity equation, so when we zero out the ds/dt, is the same as saying the velocity went to 0, since it got zeroed out, and then the particle goes over the vertex and changes direction.
the negative acceleration value, simply means a decreasing rate of change, so, it means the particle is slowing down and possibly coming to a stop before changing direction again.