Perhaps you meant <span>(a^3+14a^2+33a-20) / (a+4), for division by (a+4).
Do you know synthetic division? If so, that'd be a great way to accomplish this division. Assume that (a+4) is a factor of </span>a^3+14a^2+33a-20; then assume that -4 is the corresponding root of a^3+14a^2+33a-20.
Perform synth. div. If there is no remainder, then you'll know that (a+4) is a factor and will also have the quoitient.
-4 / 1 14 33 -20
___ -4_-40 28___________
1 10 -7 8
Here the remainder is not zero; it's 8. However, we now know that the quotient is 1a^2 + 10a - 7 with a remainder of 8.
R+2=3. I hope this helped and please mark this as brainliest answer.
Answer:
Length = 6
Width = 3/2
Step-by-step explanation:
You can choose to go about this question in lots of different ways, but this is how i did it. I drew a diagram of the rectangle and labeled it: the height/length as x and the width as x/4 (they told us the width is a quarter of the length). They also told us that the area is 9 square units.
We know that length x width = area
So: length x width = 9
I'm gonna bring in the variables i used in the diagram, so:
x
= 9
Keep solving:
= 9
Times both sides by 4:
= 36
Square root both sides for x:
<em>* remember that when you square root, its possible to have a positive or negative version of the value</em>
x = ±6
Since its impossible to have a negative length, we can say that x = 6.
X was just the variable we gave to the length of the rectangle, so now we know the length is 6. If you needed to find width as well, you can do 6/4, which simplifies to 3/2.
To double-check
- 6 x 3/2 should equal 9, since length x width = area
which it is, so we're correct!
Hope that helped : )
Carina can assemble 10 products within the give time
<u>ANSWER</u>
The zeros are 
EXPLANATION
Given;
.
We can rewrite the function as



The zeros are found by equating the function to zero.


The multiplicity is 1, since it is odd the graph crosses at this intercept. which is 
Or

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is 
Or

This last root has a multiplicity of 2.
That is
repeats two times.
Since the multiplicity is even, the graph touches the x-axis at the point
.
See graph.