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topjm [15]
3 years ago
8

What is the greatest common factor of 20 and 30???

Mathematics
1 answer:
Ugo [173]3 years ago
7 0
The greatest common factor of 20 and 30 is 10. This is because 10 is the largest number that when it is used to divide 20 or 30, it equals a whole number.

The simple way for us to solve is to write down the factors of both numbers, find the factors that match for both numbers, and see which is the largest out of those that match.

20: <u>1</u>,<u>2</u>,4,<u>5</u>,<u>10</u>,20
30: <u>1</u>,<u>2</u>,3,<u>5</u>,6,<u>10</u>,15,30

Using that logic, we can see that 10 is the greatest factor that the numbers share.

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4 0
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In the figure shown to the right, two angle measurements are given. Determine the others.
creativ13 [48]

The figure is shown below

From the figure

Angle 150 degree and angle p forms angles on a straight

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Hence

150^{\circ}+p=180^{\circ}

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From the figure

Angle p and angle q are vertically opposite angles

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q+w+60=180

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Solve for w

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8 0
1 year ago
Help me with question a please ! With full workings !
frosja888 [35]
A)


\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;Q&({{ 0}}\quad ,&{{ 2}})\quad &#10;%  (c,d)&#10;P&({{ 0.5}}\quad ,&{{ 0}})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}

\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}&#10;\\\\\\&#10;QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}&#10;\\\\\\&#10;QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)


c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;Q&({{ 0}}\quad ,&{{ 2}})\quad &#10;%   (c,d)&#10;R&({{ -0.5}}\quad ,&{{ 0}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}

\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4&#10;\\\\\\&#10;% point-slope intercept&#10;y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\&#10;\left. \qquad   \right. \uparrow\\&#10;\textit{point-slope form}
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