Answer:
The frequency of the note a perfect fifth below C4 is;
B- 174.42 Hz
Step-by-step explanation:
Here we note that to get the "perfect fifth" of a musical note we have to play a not that is either 1.5 above or 1.5 below the note to which we reference. Therefore to get the frequency of the note a perfect fifth below C4 which is about 261.63 Hz, we have
1.5 × Frequency of note Y = Frequency of C4
1.5 × Y = 261.63
Therefore, Y = 261.63/1.5 = 174.42 Hz.
20 x 3/4 =
20/1 x 3/4= turn the 20 into a fraction
20 x 3 / 1 x 4
60/4 =
15
The answer is 15. :)
Answer:
Step-by-step explanation:
Area of the rectangular piece A = xy
x is the length
y is the width
Perimeter =2x+2y
Given
Perimeter = 3044yds
3044 = 2x+2y
1522 = x+y
x = 1522-y
Substitute into the formula for area
A = xy
A = (1522-y)y
A = 1522y-y²
To maximize the area, dA/dy must be zero
dA/dy = 1522-2y
0 = 1522-2y
2y = 1522
y = 1522/2
y = 761
Since x+y = 1522
X+761 = 1522
X = 761
Dimension is 761yd by 761yd
Area = 761×761 = 579121yd²
See attached photo for solution
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